Construct a polynomial function with the stated properties. Reduce all fractions to lowest terms. Third-degree, with zeros of −4, −2, and 3, and a y-intercept of −13. p(x) =
Okay so we need to find a polynomial, \(p(x)\) with zeroes \(x = 4, x = 2, x = -3\) with y-intercept of -13. We know that p(x) will be some form of \(p(x) = a(x - 4)(x - 2)(x + 3)\) right?
yes
Okay now, since the y-intercept is -13, that means the y-intercept of \(p(x)\) is the point \((0,-13)\) In other words \(p(0) = -13\)
So we can plug that point in to our equation for \(p(x)\):
\(-13 = a(0 - 4)(0 - 2)(0+3)\)
Then solve for \(a\)
\(-13 = a(-4)(-2)(3)\)
a = -13/24
Yes, however, I meant to write \(p(x) = a(x + 4)(x + 2)(x - 3)\) so a = 13/24
So \(p(x) = \dfrac{13}{24}(x + 4)(x + 2)(x - 3)\)
wow thank you hero
You're welcome
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