Find the perimeter of the triangle whose vertices are (−1,−6), (14,2), and (8,−6). Write the exact answer. Do not round.
i'm thinking is the answer 36 or 42
@vocaloid
why two answers? what did you get when you used the distance formula?
i was confused by the formula i wasn't sure
SqRt(-1–14)^2+ (-6–2)^2 = 17 units: ….SqRt (14–8)^2+ (2+6)^2 = 10 units and SqRt (-1–8)^2+ (-6*6)^2 = 9 units (17+10+9 = 36 units)
Using distance formula: PQ=sqrt((x2-x1)^2(y2-y1)^2), AB= 17 BC= 10 AC= 15 Perimeter= 17+10+15 = 42
numbers in the first post are accurate, the sides are 10, 17, and 9 making the perimeter 36 i don't know where they're getting 15 in the second post
okay , i wanted to see which one of them were right because i think i put it together in the formula wrong for the 2nd one.
For the following equation, determine the values of the missing entries. Reduce all fractions to lowest terms. 4x−2y=12 Note: Each column in the table represents an ordered pair. If multiple solutions exist, you only need to identify one. x ________ 0 2 __________ y 0 ______ _______ 5
in each column, take what's there, and plug it into the equation to figure out what the missing variable is so for the first column, y = 0, so 4x−2y=12 ----> 4x - 2(0) = 12 ----> 4x = 12, x = 3 so you'd plug in x = 3 into the first column repeat with the other values
x 3 0 2 11/2 y 0 3 4 5
is this right
review equations when you get a chance 4x−2y=12 for x = 0 ---> 4(0) - 2y = 12 dividing both sides by -2 ----> y = -6 for x = 2 ----> 4(2)−2(y)=12 ---> 8 - 2y = 12 ---> -2y = 8 ---> y = -4 last column is correct
x 3 0 2 11/2 y 0 -6 -4 5
is this right now
I made an arithmetic mistake: 8 - 2y = 12 ---> -2y = 4 ---> y = -2 in the third column
Oh okay x 3 0 2 11/2 y 0 -6 -2 5
good
Find the perimeter of the triangle whose vertices are (−1,−8), (4,−8), and (4,4). Write the exact answer. Do not round.
Sketch the triangle, use the distance formula on all three sides
p = 36.791
check your arithmetic again, it should be a whole number solution to make this simpler: (4,−8), and (4,4) are on the same vertical line. -8 and 4 are 12 units apart, so the distance between (4,−8), and (4,4) is 12, so this side is 12 units long. similar logic with (−1,−6) and (8,−6), they're on the same horizontal line. the distance between -1 and 8 is 9 units, so this side is 9 units long. only side left is between (−1,−6), (14,2) which you'll need the distance formula for.
(−1,−6), (14,2) ----> (14, -1), (6, 2)
when you're using the distance formula, you get a distance, so your answer should only be one number your points are: (−1,−6), (14,2) let (x1,y1) = (-1,-6) and (x2,y2) be (14,2) plug the numbers into the distance formula
(-6, -1) , (2, 14)
like I mentioned, when you use the distance formula, your answer should just be one number.
please review the distance formula: \[d = \sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}\] let (x1,y1) = (-1,-6) and (x2,y2) be (14,2) plugging in: \[d = \sqrt{(14-(-1))^{2}+(2-(-6))^{2}}\]simplify
2√65
ugh sorry I think I used the wrong points (−1,−8), (4,−8), and (4,4)
try the distance formula again with (-1,-8) and (4,4)
oh it's okay
it seemed out of order in the beginning
(-1,-8) and (4,4) √4 - (-8))^2 + (4 - (-1))^2
good, that simplifies to 13 looking at the other points: (4,−8), and (4,4) ---> these are both on the same vertical line because they have the same x-coordinate. so just take the difference of the y-coordinates: 4 - (-8) = 12 (−1,−8), (4,−8) ---> these are on the same horizontal line, take the difference of the x-coordinates ---> 4 - (-1) = 5 so your sides are: 5, 12, 13 ---> sum = perimeter = 30
thank you
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