Among all rectangles that have a perimeter of 64, find the dimensions of the one whose area is largest. Write your answers as fractions reduced to lowest terms. ____________, _____________
@vocaloid
What math class is this?
Algebra, this is Quadratic Functions
Intermediate Algebra
Okay, just making sure it isn't calculus. So since this is not calculus you do guess and check to find the dimensions with the largest area. You will find a square to have a larger area than say, a rectangle of the same perimeter. It would be pretty cool if you try this for yourself as well. Plug in 16 and 16 for length and width, 20 and 12 for length and width (respectively), a few more length and widths that have a total Perimeter of 64, and see which has the greatest Area. Remember: A = L* W P = 2(L+W)
P = 2(16+12)
?
Plug these in for L and W respectively (16, 16) (12, 20) (2, 30) (15, 17) into the area formula, I have already checked and the perimeter for each of these is 64. See which of these had the greatest Area
like this: A = L* W A = 16 * 16 ?
yes, now 16 times 16 is....?
256
yes, now do the same for the other coordinates
12 * 20 = 240 2 * 30 = 60 15 *17 = 255
good job, so you found that 16*16 gives the largest area
So your answer, or the largest rectangles dimensions, are (16, 16) write 16 over both or the underlines in the question
i could only do it like this
?
Yes, you can submit
ok
could you answer more for me
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