Question

MATH HELP PLEASE:

Answer 1

\[y=a(x-h)^2+k\]
to find axis of symmetry
put x-h=0
x=h
axis of symetry is x=h
where (h,k) is vertex.

Answer 2

Ok so what do i do because i have no idea where to start

Answer 3

for f(x)
\[f(x)=-4(x-8)^2+3\]
compare with \[y=a(x-h)^2+k\]
x-h=?

Answer 4

put x-8=0
axis of symmetry is x=8

Answer 5

vertex for h(x)=?

Answer 6

Ok so the axis of symmetry for f(x) is x = 8

Answer 7

yes

Answer 8

do you know the vertex of h(x)?

Answer 9

No sir

Answer 10

it is the highest point of h(x),which has coordinates (3,2)
so axis of symmetry is x=3

Answer 11

Ohhh ok now i see

Answer 12

So question does x = 8 and x = 3 split each one of their functions in half?

Answer 13

for f(x),it is x=8
and for h(x) ,it is x=3

Answer 14

Ok thanks but we need to tell an explanation on how we got the answers

Answer 15

Nvm i got it thanks for the help