Which of the following explains the VSEPR geometry of a water molecule?

It is tetrahedral because there are four bonded pairs around oxygen.
It is bent because there are four bonded pairs around oxygen.
It is tetrahedral because there are two bonded pairs and two lone pairs around oxygen.
It is bent because there are two bonded pairs and two lone pairs around oxygen.

Question

Which of the following explains the VSEPR geometry of a water molecule?

It is tetrahedral because there are four bonded pairs around oxygen.
 It is bent because there are four bonded pairs around oxygen.
 It is tetrahedral because there are two bonded pairs and two lone pairs around oxygen.
 It is bent because there are two bonded pairs and two lone pairs around oxygen.

kekeman · Answer

Could you help me real fast @tranquility

kekeman · Answer

I know it is not D.)

kekeman · Answer

The molecular shape of water is bent and the VSEPR/ electron geometry is Tetrahedral

kekeman · Answer

I think its C.) " It is tetrahedral because there are two bonded pairs and two lone pairs around oxygen."

kekeman · Answer

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Tranquility · Answer

@kekeman wrote:

I think its C.) " It is tetrahedral because there are two bonded pairs and two lone pairs around oxygen."

That is correct. VSEPR geometry only accounts for the number of electron groups around the central atom. Which is different from the molecular geometry which differentiates based on number of lone pairs.

kekeman · Answer

Thanks!

Tranquility · Answer

No problem!

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