Question

i need help

Answer 1

uhm hello?

Answer 2

@extrinix

Answer 3

@thisgirlpretty

Answer 4

i guess no one is going to help me

Answer 5

@joe348

Answer 6

So it's easier to convert \(f(x)=zx+b\) to inverse than it is to convert \(f^{-1}(x)=zx=b\)

Let's start off with \(f(x)=2x-8\)

Understand that we need to switch y and x, then solve for y.
\(y=2x-8\)
Swap them
\(x=2y-8\)

Now solve the equation, what would you get?

Answer 7

\[\frac{ x+8 }{ 2}\]

Answer 8

so the first one goes with the second one

Answer 9

Which would give you \(\dfrac{1}{2}x+4\), which is your inverse

Inverse:
\(f^{-1}(x)=\dfrac{1}{2}x+4\)

Answer 10

Correct ^^

Answer 11

Most teachers don't force you to simplify completely, but knowing how to simplify it completely could help if there's a question that asks for it...

Answer 12

Anyways, onto #2

\(f(x)=2x+7\)

Swap x and y then solve for y, as the other one was
\(x=2y+7\)

What would you get?

Answer 13

Good job, you're catching the hang of it ^^

Answer 14

i think the last one is f(x)=1/x+2