Question

math

Answer 1

16+24x-35

Answer 2

16+24x-35
16+-35= 51
51*24=
x= 1224
there you go joe

Answer 3

Eve, that is incorrect. We are completing the square, NOT solving for x right now.

Answer 4

The first thing you have to do is get (-35) to the other side of the equation so that it can become our constant (which is c).

So we have to add -35 from both sides.

\[4x ^{2}+24x~ (+35)=-35~(+35)\]

do you understand?

Answer 5

add 35*

Answer 6

yes

Answer 7

so \[4x^2+24x+35=0?\]

Answer 8

yes, correct, that was i was about to write :)

Now, we can do this 2 ways, we can factor this out OR you can use the quadratic formula. which do you prefer?

Answer 9

what is the quadratic formula?

Answer 10

oh the little b+ thingy?

Answer 11

yes, personally i think factoring is easier, which do you want to do?

Answer 12

which ever is easy for you to help me.

Answer 13

alright, so first off, do you know how to factor?

Answer 14

no😐

Answer 15

oh, do you at least know the concept? or how to do it?

if you dont, here are a few tutorials:

https://www.mathsisfun.com/algebra/factoring-quadratics.html

https://www.cuemath.com/algebra/factorization-of-quadratic-equations/

https://www.youtube.com/watch?v=ZQ-NRsWhOGI

Answer 16

well ill just use the quadratic

Answer 17

yea lets do that one instead...

Equation:

\[x =\frac{ -b \pm \sqrt{b ^{2}-4(a)(c)} }{ 2a }\]

you know your a,b, and c values, right?

Answer 18

uh let me see

Answer 19

a=4
b=24
c=35

Answer 20

right?

Answer 21

yes :D

Answer 22

okay now what?

Answer 23

plug in the values and solve... lemme make it a little easy and help...

\[x =\frac{ -24 + \sqrt{24 ^{2}-4(4)(35)} }{ 2(4) }\]

\[x =\frac{ -24 - \sqrt{24 ^{2}-4(4)(35)} }{ 2(4) }\]

basically, you solve for x for each one...

Answer 24

okay I got it now thank you

Answer 25

ok great, what did you get as your final answers?