Brad can make 4 key chains in an hour. Velma can make only 3 key chains in an hour, but she already has 6 completed key chains. Explain to Brad how he can use a system of equations to determine when he will have the same number of key chains as Velma. Use complete sentences.
@vocaloid ,I had a feeling you were going to ask that.But,specifically for some reason I wasn't given a diagram to work with....The question shown is as is,hopefully this sorts the clarification in such ways.
Okay some clarification questions: Can Brad's number of keychains be larger than Velma's, or does the values have to be the exact same? Also, can Velma's number of keychains increase, or does it have to stay static? Last one, can the number of keychains be decreased, or does it HAVE to increase?
@bruhgetrekt, as for your 1st question;I assume that I or whoever is working out this problem has to then go on to find the steps.Steps being on determining if Brad's number of keychains is larger than Velma's, or that the values have the exact same possibility,etc. Overall,the question that I was given, asked that I had to answer the question itself in complete sentences;so for your three questions it can go either way. But , I'm not fully sure myself @bruhgetrekt .
So I'm assuming the equation has to involve time because the question asks "when" he will have more keychains. So basically we're trying to help brad find out when he will have more keychains than Velma? Like how many hours it will take for him to catch up and surpass her?
Yes
@surjithayer can help you though
let t be number of hours when both have the same number of key chains. if y is the number of chains for Brad number of key chains y=4t for Velma number of key chains y=3t+6 4t=3t+6 4t-3t=6 t=6 so after 6 hours both have same number of chains.
@surjithayer,thank you for clarifying I really appreciate it.
yw
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