x^3-34x-12=0

Do you know the solution set?

Question

x^3-34x-12=0

Do you know the solution set?

GalaxyzStarz · Answer

As in a factored form?

Kyky232 · Answer

I dont even know. Its algebra 2

GalaxyzStarz · Answer

$$(x  \pm?)(x \pm ?)$$
Like that?

Kyky232 · Answer

attachment

Kyky232 · Answer

thats the question

GalaxyzStarz · Answer

Is B.) correct or incorrect?

Kyky232 · Answer

I got part B incorrect. The first part was C

GalaxyzStarz · Answer

I need the correct answer for B.) to use on C.)

Kyky232 · Answer

the answer for b is 6, i just got it wrong the first time

surjithayer · Answer

factors of 12 are $$\pm1,\pm2,\pm3,\pm4,\pm6$$
by hit and trial method put x=1,2,3,4,5,6
when we put x=6
$$6^3-34\times6-12=216-204-12=0$$
so one solution is x=6
by synthetic division
6| 1  0  -34   -12
  | -   6   36     12
  |
<hr class="bbcode_rule" />
1  6    2   |0
$$x^2+6x+2=0$$
$$x=\frac{ -6 \pm \sqrt{6^2-4\times1\times2} }{ 2\times2}$$
$$x=\frac{ -6 \pm \sqrt{36-8} }{ 2}=\frac{ -6 \pm \sqrt{28} }{ 2 }=\frac{ -6 \pm 2\sqrt{7}}{ 2}$$
$$x=-3 \pm \sqrt{7}$$

QueenNiyah · Answer

x=6

surjithayer · Answer

$$solution~set~is~$$$$ (-3-\sqrt{7},-3+\sqrt{7},6)$$

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