Idk what this is. Please help :3

Question

UkuleleGirl · Answer

attachment

Cyber · Answer

@tetsxpreme Please help this user

jacob65 · Answer

Alright i can help if your ok witht hat

UkuleleGirl · Answer

I don't think tet knows this.

Cyber · Answer

I think a mathlete should know

UkuleleGirl · Answer

ok

jacob65 · Answer

I can help

UkuleleGirl · Answer

please do.

jacob65 · Answer

Alright are we solving for x?

UkuleleGirl · Answer

I think were supposed to factor.

UkuleleGirl · Answer

I need dude online. He knows all about this.

jacob65 · Answer

ok go pm him then

UkuleleGirl · Answer

Hes not on.

jacob65 · Answer

Oh alright

UkuleleGirl · Answer

oh wait he is.

UkuleleGirl · Answer

@dude

UkuleleGirl · Answer

-_- he went offline.

jacob65 · Answer

lol i dont remember how to fractor it its been years but I bet i could help solve it

UkuleleGirl · Answer

I know how to factor

jacob65 · Answer

then whats the issue

UkuleleGirl · Answer

I always get stuck on here. Don't question me.

jacob65 · Answer

bruh dont ask for help then lol

UkuleleGirl · Answer

I need help....breh. You don't get to tell me what to do ON MY question.

UkuleleGirl · Answer

Get out if your not going to help

YTStresssPG3D · Answer

@ukulelegirl wrote:

Get out if your not going to help

they said they was going to help u

YTStresssPG3D · Answer

like chill

UkuleleGirl · Answer

They were being rude and im not in the mood. Just help me please...

UkuleleGirl · Answer

I dont' feel like gettin yelled at again by my mom

YRJ8498 · Answer

@ukulelegirl wrote:

I dont' feel like gettin yelled at again by my mom

LMAO

YTStresssPG3D · Answer

@jacob65 wrote:

Alright i can help if your ok witht hat

uh no because of that

UkuleleGirl · Answer

THEN LEAVE IM NOT IN THE MOOD

UkuleleGirl · Answer

Just go...

YTStresssPG3D · Answer

shoula let thm help u

UkuleleGirl · Answer

OK just go. This convo is over.

Cyber · Answer

Here I will help you get someone @ukulelegirl

Cyber · Answer

@joe348

UkuleleGirl · Answer

Your supposed to factor-

YTStresssPG3D · Answer

@ukulelegirl wrote:

Your supposed to factor-

no direct answers

UkuleleGirl · Answer

but this always confusesssss meeeeeeeee T_T

UkuleleGirl · Answer

me and you both know thats not the answer

RodWav3 · Answer

oh damn

ThisGirlPretty · Answer

For those that don't know how to help the user please refrain from making any comments. Instead it would be more helpful if we pinged the users that were good in math.

UkuleleGirl · Answer

Exactly.

UkuleleGirl · Answer

This is why we need dude. or someone smart like tet, joe, noodles, them peoople

jacob65 · Answer

I offered to help and she continued to be rude about it so i left

Joe348 · Answer

Well have you tried solving the equation? @ukulelegirl

YTStresssPG3D · Answer

@jacob65 wrote:

I offered to help and she continued to be rude about it so i left

yes he was trying to answer but she was being rude

UkuleleGirl · Answer

ok if your going to start on me jacob i can be rude. now leave. thanks. im trying to learn.

YTStresssPG3D · Answer

or she

UkuleleGirl · Answer

And no joe...I'm confused...i would say combine like terms but there isn't anything u can combin here

YTStresssPG3D · Answer

@ukulelegirl wrote:

ok if your going to start on me jacob i can be rude. now leave. thanks. im trying to learn.

he was trying to help u if u dont want help from people offering it then take the question down.

jacob65 · Answer

Im a she lol  and i did leave and ur still going i tried to help yet you were being the rude one seriosuly

YTStresssPG3D · Answer

@jacob65 wrote:

Im a she lol and i did leave and ur still going i tried to help yet you were being the rude one seriosuly

i said or she and yes

iFish · Answer

I can answer this question, if you guys would quit talking.

jacob65 · Answer

thank you

UkuleleGirl · Answer

JUST SHUT UP UNLESS U CAN HELP DANG

YTStresssPG3D · Answer

@ifish wrote:

I can answer this question, if you guys would quit talking.

she doesnt want help from anyone thats not smart she will not take your answer

UkuleleGirl · Answer

its not that.

Joe348 · Answer

@ukulelegirl wrote:

And no joe...I'm confused...i would say combine like terms but there isn't anything u can combin here

your not combining your trying to solve for the equation first

TETSXPREME · Answer

@hero

UkuleleGirl · Answer

I know were not. which is why im confused. Im stuck.

iFish · Answer

I can answer this question, just let me speak.

UkuleleGirl · Answer

go ahead

iFish · Answer

Do you know how to factor the equation?

UkuleleGirl · Answer

It says this is factor by grouping.

iFish · Answer

Grab a sheet of paper, and write this information down, please.

UkuleleGirl · Answer

ok brb

UkuleleGirl · Answer

alr im here.

UkuleleGirl · Answer

@yrj8498 wrote:

@ytstressspg3d wrote:

@ifish wrote:

I can answer this question, if you guys would quit talking.

she doesnt want help from anyone thats not smart she will not take your answer

Stress leave the question so she could get a real answer and not ppl calling her rude I would want sm1 smart answering my question too

Exactly thank you

Joe348 · Answer

$$(x+1)(2x+1)(2x-1)=0$$

YTStresssPG3D · Answer

@ukulelegirl wrote:

@yrj8498 wrote:

@ytstressspg3d wrote:

@ifish wrote:

I can answer this question, if you guys would quit talking.

she doesnt want help from anyone thats not smart she will not take your answer

Stress leave the question so she could get a real answer and not ppl calling her rude I would want sm1 smart answering my question too

Exactly thank you

well someone was just trying to help and she continued to be rude.

UkuleleGirl · Answer

you factored out 2 from 4?

ThisGirlPretty · Answer

Guys let's stay on topic please

UkuleleGirl · Answer

Thank you tgp. <3

UkuleleGirl · Answer

@joe348 wrote:

$$(x+1)(2x+1)(2x-1)=0$$

DId you factor out 2 from 4

UkuleleGirl · Answer

@hero

UkuleleGirl · Answer

Joe is that the answer or???

UkuleleGirl · Answer

I'm confused..

jacob65 · Answer

bro be patient

Joe348 · Answer

sorry, im a lil laggy

UkuleleGirl · Answer

I'm sorry this is making me very frustrated...Please excuse me If I go offline for a bit. I just am about to lose it.

UkuleleGirl · Answer

and your fine joe

Hero · Answer

Someone posted the answer but they did not provide any steps or explanations. Really sad.

UkuleleGirl · Answer

Yes.

UkuleleGirl · Answer

What sucks is i have more like these.

ThisGirlPretty · Answer

Think you can help her hero?

YRJ8498 · Answer

@tetsxpreme

Timmyspu · Answer

Could you provide the steps for why that is the answer hero?

Hero · Answer

Yes

CheeseStick7793 · Answer

i c an helppppppp

UkuleleGirl · Answer

Knock yourself out.

Hero · Answer

So we have $4x^3 + 4x^2 - x - 1 = 0$ and we have to factor by grouping. So the first step is to factor the first two terms and the last two terms. $4x^2$ can be factored from the first two terms and $-1$ can be factored from the last two terms. Upon doing so you get:
$4x^2(x + 1) -1(x + 1)$

Next, observe that $x+1$ is common to both factorizations, so factor that out as well to get:
$(x+1)(4x^2 -1)$

Finally, observe that $4x^2 - 1$ is a difference of squares. Then factor it to get:
$(x+1)(2x+1)(2x-1)$

Joe348 · Answer

@joe348 wrote:

$$(x+1)(2x+1)(2x-1)=0$$

$$4x^3+x^2)+(-4x-1)=0$$ $$x^2(4x+1)-1(4x+1)=0$$ $$(x^2-1)(4x+1)=0$$

Joe348 · Answer

@joe348 wrote:

$$(x+1)(2x+1)(2x-1)=0$$

$$4x^3+x^2)+(-4x-1)=0$$ $$x^2(4x+1)-1(4x+1)=0$$ $$(x^2-1)(4x+1)=0$$

(4x^3)

CheeseStick7793 · Answer

(x+1)(2x-1)(2x+1)

UkuleleGirl · Answer

uhhhhhhh.

CheeseStick7793 · Answer

trust me

Joe348 · Answer

That's how I got it but it's not the answer

CheeseStick7793 · Answer

that is your answer

CheeseStick7793 · Answer

(x+1)(2x-1)(2x+1)

UkuleleGirl · Answer

OMG. its so confusing.

CheeseStick7793 · Answer

mine is right

UkuleleGirl · Answer

I think I'm really going to have to do more of these to understand a bit more

CheeseStick7793 · Answer

Answer: (x+1)(2x-1)(2x+1)

Hero · Answer

The steps

@hero wrote:

So we have $4x^3 + 4x^2 - x - 1 = 0$ and we have to factor by grouping. So the first step is to factor the first two terms and the last two terms. $4x^2$ can be factored from the first two terms and $-1$ can be factored from the last two terms. Upon doing so you get: $4x^2(x + 1) -1(x + 1)$ Next, observe that $x+1$ is common to both factorizations, so factor that out as well to get: $(x+1)(4x^2 -1)$ Finally, observe that $4x^2 - 1$ is a difference of squares. Then factor it to get: $(x+1)(2x+1)(2x-1)$

@UkuleleGirl, the steps I provided are the correct steps.

CheeseStick7793 · Answer

you are wrong

UkuleleGirl · Answer

How is he wrong? hes literally like one of the smartest people here.

CheeseStick7793 · Answer

beacuse i calculated and checked my work

CheeseStick7793 · Answer

and i got (x+1)(2x-1)(2x+1)

UkuleleGirl · Answer

Thats what he got.

CheeseStick7793 · Answer

he did not g et the same the math symbols are switched

Hero · Answer

BTW, the problem is still not finished @UkuleleGirl. You still have to solve for $x$

UkuleleGirl · Answer

Set them equal to 0 and solve yes i know this part

CheeseStick7793 · Answer

(x+1)(2x-1)(2x+1)

chrisdjackson · Answer

U still need help with this equation?

UkuleleGirl · Answer

is the answers, $$-1, -\frac{ 1 }{ 2 },\frac{ 1 }{ 2 }$$

Hero · Answer

Yes correct @UkuleleGirl

UkuleleGirl · Answer

Yay!

UkuleleGirl · Answer

Smh math is hard

CheeseStick7793 · Answer

Factor by grouping
Factor by grouping
Factor by grouping
Factor by grouping
(x+1)(4x^2-1)
Find one factor
Factor by grouping
Factor by grouping
Factor by grouping
Factor by grouping
(x+1)(2x-1)(2x+1)

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