Question

help pls

Answer 1

you have my math?!

Answer 2

GIRL IM LITERALLY DOING THIS MATH

Answer 3

were going to do factoring.

Answer 4

ok so you know what the x method is

Answer 5

the one for factoring?

Answer 6

oh yeah i know the x factor

Answer 7

Yes. so what you wanna do is put 27 at the top and -12 at the bottom. Divide 27 by all the numbers until u find out what adds or subtracts to -12 and multiplies to 27.

Answer 8

-9 and - 3

Answer 9

Yesh

Answer 10

.\[\frac{ (x-9)(x-3) }{ (x+3)}\] this is what you have now. this is the first side.

Answer 11

yes but wouldnt it be different bc it has degrees

Answer 12

no it doesnt...

Answer 13

the variables have powers of more than 2

Answer 14

oh yea..

Answer 15

well we factored..

Answer 16

i was just wonderig if it would have a different outcome because of the powers

Answer 17

lets continue on the line first. then if its wrong we will Salsa that.

Answer 18

uhhhhhhhh

Answer 19

I think i spelled that wrong.

Answer 20

lol

Answer 21

I meant acess.

Answer 22

ok so what we do next

Answer 23

ok to make it easier. lets do the bottom on the other side first.

Answer 24

factor that side.

Answer 25

the same as what we did on the other one

Answer 26

but this time. make sure you multiply 6 and 324.

Answer 27

whatever u get, should be at the top of your x

Answer 28

0-0 aparenty i was wrong so I got someone to help you

Answer 29

@vocaloid

Answer 30

this is super easy if you use https://www.desmos.com/calculator all you have to do is type in the question and it gives you the answer. this is useful for highschool math.

Answer 31

Given:
\[\frac{ x^5-12x^4+27x^3 }{ x+6 } \times \frac{ 2x^2-72 }{ 6x^2-90x+324 }\]
Start out with second fraction and factor:\[2x^2-72\]
Rewrite it as:\[72 = 2\times36\]
Factor out common term, which is 2:
\[=2(x^2-36)\]
Now we factor out what's in the parentheses:
\[x^2-36\]
Rewrite that as:\[36=6^2\]
Apply difference of two squares formula (example):
\[x^2-y^2=(x+y)(x-y)\]
Our's should look like this:
\[x^2-6^2=(x+6)(x-6)\]
\[=(x+6)(x-6)\]
\[=2(x+6)(x-6)\]
So now it should look like so:
\[=\frac{ 2(x+6)(x-6) }{ 6x^2-90x+324 }\]
Now to factor the bottom half:
Rewrite it as:\[90=6 \times15\]\[324=6 \times54\]
Should look like this:\[=x^2-6\times15x+6\times 54\]
Factor out common term, which is 6:
\[=6(x^2-15x+54)\]
Factor out:
\[x^2-15+54\]
Break the expression into groups (example):
\[(ax^2+ux)+(vx+c)\]
Our's should look like this:
\[(x^2-6x)+(-9x+54)\]
Factor out x from:
\[x^2=6x\]
Apply exponent rules (example): \[a^b+c=a^b a^c\]
Our's should look like this:\[x^2=xx\]
\[=xx-6x\]
Factor out common term, which is x:
\[=x(x-6)\]
Now for:\[-9x+54\]
Rewrite:\[54=-9 \times 6\]
Factor out common term, which is -9:
\[=-9(x-6)\]
Should look like this now:
\[=6(x-6)(x-9)\]
\[=\frac{ 2(x+6)(x-6) }{ 6(x-6)(x-9) }\]
Cancel common factor, x-6:
\[=\frac{ 2(x+6) }{ 6(x-9) }\]
Factor the number, 6 = 3*3
\[=\frac{ 2(x+6) }{ 6(x-9) }\]
Cancel the common factor, 2:
\[=\frac{ x+6 }{ 3(x-9) }\]
\[=\frac{ x^2-12^4+27x^3 }{ x+6 } \times \frac{ x+6 }{ 3(x-9) }\]
Cross cancel common factor, x +6:
\[=\frac{ x^2-12x^4+27x^3) }{ 3(x-9) }\]
Therefore, your final answer is:
\[=\frac{ x^2-12x^4+27x^3) }{ 3(x-9) }\]