Question

Determine the solution to the system of equations graphed below and explain your reasoning in complete sentences.

Answer 1

Could you show a screenshot please?

Answer 2

yes give me a second @ukulelegirl

Answer 3

I recommend you use this This is Desmos Graphing calculator

Answer 4

Click on the link.

Answer 5

i clicked on the link but im not sure as to what im supposed to write in my answer box.. I assume that I put both equations into desmos but what action should i take afterwards.

Answer 6

both the graphs cut at (0,1)
the solution is the point which lies on both the functions.
Hence the solution is x=?
y=?

Answer 7

so i would type "since both graphs cut at (0,1) the answer is x=y:? @surjithayer

Answer 8

They went offline

Answer 9

oh okay thanks for letting me know

Answer 10

I'm getting someone else.

Answer 11

okay much appreciated

Answer 12

Wait wait I think I get it now.

Answer 13

Okay I understand what they were talking about

Answer 14

Okay I'm listening

Answer 15

So they said look where the point lies on both of the functions

Answer 16

I'm looking at the graph and it would only make sense for the intersection of 2 lines at one point

Answer 17

the intersection would be (0,2) correct?

Answer 18

correct the solution is (0,2)

Answer 19

Thanks! I appreciate the help.

Answer 20

g(x)=3x+2 notice that g(x)=y
our solution is a point (x,y)
so lets apply that
we have the point (0,2)
y=g(x)
y=2
and x=0
2=3(0)+2
So 2=2
the point is a solution apply that for the other equation

Answer 21

correction
they both cut at (0,2)
so the solution is x=0,y=2

Answer 22

yes you are correct.
it cuts at (0,2)

Answer 23

g(x)=3x+2
let g(x)=y
y=3x+2 ...(1)
f(x)=|x-1|+1
let f(x)=y
y=|x-1|+1
\[y=\pm (x-1)+1\]
if x>1
either y=x-1+1=x
x=3x+2
2x=-2
x=-1
rejected as x>1
or x<1
x-1<0
y=-(x-1)+1=-x+2
-x+2=3x+2
4x=0
x=0/4=0
y=3(0)+2=2
Hence solution is (0,2)