Question

a first order reaction has a 1/2 life of 63.4 mins at 225 degrees C. Calculate the rate constant for the reaction

Answer 1

I just need help with the equation

Answer 2

Well to find the half life, you'd use
\[t1/2=\frac{ \ln (2)}{ k }\]
where "k" is the rate constant.

So just flip the rate constant and half life around:
\[k=\frac{ \ln (2) }{ t1/2 }\]
Divide the natural log of 2 by the half life (63.4 minutes) and you end up with the answer in seconds.

Answer 3

e