Question

9) f(x) —x2 + 4x— 3
x intercept(s)
axis of symmetry

Answer 1

when f(x)=0
\[-x^2+4x-3=0\]
\[-x^2+3x+x-3=0\]
\[-x(x-3)+1(x-3)=0\]
(x-3)(-x+1)=0
x=3,x=1
so x intercepts are (1,0) and (3,0)
to find axis of symmetry.
\[f(x)=-(x^2-4x+4-4)-3\]
\[f(x)=-(x-2)^2+4-3\]
\[f(x)=-(x-2)^2+1\]
it is a downward parabola with vertex (2,1)

Answer 2

axis of symmetry is x-2=0
or
x=2