Question

Help plzzs

Answer 1

idk

Answer 2

arent u a grown man tho

Answer 3

im a female

Answer 4

Sorry, that was my friend-

Answer 5

Oh-

Answer 6

Um, sorrry hehe-

Answer 7

that's my guy best friend im in 9th grade rude

Answer 8

\[f(x)=x^2-6x+5=x^2-6x+9-9+5=(x-3)^2-4\]
vertex (3,-4)
axis of symmetry x-3=0,or x=3
when x=0,f(x)=5
y intercept=5 or (0,5)

Answer 9

for x-intercepts
put f(x)=0
\[x^2-6x+5=0\]
\[x^2-x-5x+5=0\]
make factors and find the value of x.

Answer 10

Just make the factors and find the value

Answer 11

idk im v much failing y geometry class

Answer 12

\[x^2-x-5x+5=0\]
\[x(x-1)-5(x-1)=0\]
(x-1)(x-5)=0
x=1,5
x-intercepts are (1,0) and (5,0)