Quadrilateral ABCD is inscribed in a circle.

What is the measure of angle A?

Enter your answer in the box.

(Image below)

Question

​Quadrilateral ABCD​ is inscribed in a circle.

What is the measure of angle A?

Enter your answer in the box.

(Image below)

Noodlearms · Answer

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Noodlearms · Answer

Is my answer correct?

Vocaloid · Answer

hmm I got something a little different

for inscribed quadrilaterals, opposite angles add up to 180

you have two opposite angles, so 3x + 1 + 2x + 9 = 180

solve for x

*important* once you have x, plug it back into m<A = 2x + 9 to get the final measurement

Noodlearms · Answer

Ohh, so it would be 180?

Vocaloid · Answer

How did you get 180?

Solving 3x + 1 + 2x + 9 = 180 gives you x = 34

Plugging it back into 2x + 9 gives you 77

Ava1 · Answer

I got 25 degrees
First you put angle A and angle C equal to each other
then you solve and fill in x in angle A's equation
2x+9=3x+1
x=8
2(8)+9
25

Ava1 · Answer

@vocaloid wrote:

How did you get 180? Solving 3x + 1 + 2x + 9 = 180 gives you x = 34 Plugging it back into 2x + 9 gives you 77

@vocaloid wrote:

hmm I got something a little different for inscribed quadrilaterals, opposite angles add up to 180 you have two opposite angles, so 3x + 1 + 2x + 9 = 180 solve for x *important* once you have x, plug it back into m

would it be angle A and angle C adding up to equal 180 or would angle's A,B,C, and D add up to equal 180? I got 25 degrees for angle A. I might be wrong

Vocaloid · Answer

Opposite angles add up to 180

Therefore angles A and C, which are opposite angles, add up to 180.

Ava1 · Answer

@vocaloid wrote:

Opposite angles add up to 180 Therefore angles A and C, which are opposite angles, add up to 180.

oh, ok

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