Question

Math help.

Answer 1

set up

y = ab^t where y is the final amount, a is the initial amount, b is the rate of decay, and t is time.

for both quantities given. 500 after 10 minutes ---> 500 = ab^10
1700 after 30 minutes 1700 = ab^30

divide the two equations

1700/500 = b^(30) / b^(10)

solve for b

once you have b, go back into either equation and solve for a

initial size is a

doubling period is the amount of time it takes for the output, y, to be twice the input, a.

so y = ab^x becomes 2a = ab^x

dividing both sides by a

2 = b^x

solve for x

population after 80 minutes ---> plug in t = 80 minutes

when will the population reach 1400 ---> plug in y = 1400 and solve for t.

Answer 2

thanks, this helped a lot