Question

In an experiment, the molar mass of the compound was determined to be 118.084 g/mol. What is the molecular formula of the compound?

Answer 1

@cutebunny123

Answer 2

Is there any more information about the compound? Like it’s empirical formula?

Answer 3

So it was a two-part question
The first question asked: Determine the empirical formula of a compound containing 40.6 grams of carbon, 5.1 grams of hydrogen, and 54.2 grams of oxygen.
Second question asked: In an experiment, the molar mass of the compound was determined to be 118.084 g/mol. What is the molecular formula of the compound?

Answer 4

So I had to find the empirical formula on my own using the first question and I got C2H3O2

Answer 5

And to solve for the next part we have to use C2H3O2 as our empirical formula

Answer 6

Calculate the molar mass of the empirical formula C2H3O2

Then divide 118.04 by that molar mass. You should get some whole number.

Multiply all the subscripts in the formula by whatever whole number you get.

Answer 7

Okay wait let me solve this and I will let you know what I get

Answer 8

The molar mass of C2H3O2 is 59.03 right?

Answer 9

I dmed you how to get the answer : )

Answer 10

Thanks!!!!!!

Answer 11

Yes, 59.03 ish, then divide the mass of the compound (108.84) / (59.03)

Answer 12

I get 2.000406573

Answer 13

So we round to the nearest whole number which is 2 right?

Answer 14

Good, and that’s very close to 2

So the actual molecule is twice the weight of C2H3O2 so to get the actual molecular formula you’d double each subscript in the empirical formula

Answer 15

C4H6O4

Answer 16

Perfect

Answer 17

Thanks!!!