Question

Hey!
I am a sophomore and I am doing geometry. This question is about circles and their equation.

as you might know...I guess...their equation is
(x−h)^2+(y−k)^2=r^2

So this is my problem, it says to WRITE the equation of the circle with the given information:

Center: (6,4)
Tangent to y = -8

Can anyone please help?

Answer 1

Figure out what the h, k and r is when the Line is tangent to the curve. H and K is given

Answer 2

Yes, I can see that, but I do not understand where I can input the Tangent to y.

Answer 3

correction
difference between (6,4) and (6,-8)
\[r=\sqrt{(6-6)^2+(-8-4)^2}=\sqrt{(-12)^2}=12\]
eq. of circle is
\[(x-6)^2+(y-4)^2=12^2\]
\[(x-6)^2+(y-4)^2=144\]