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Fortish:
@uhhhkhakis wrote:
I'm sorry fam I'm bad at math.
Same xd
Aqual:
I'm looking now
AsleepAndUnafraid21:
ty
Aqual:
Fist you're going to give the perimeter of cgrp
Aqual:
So use \[p = 2(a+b)\]
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Aqual:
p + 2(side + base)
Aqual:
p = 2(400 + 600)
AsleepAndUnafraid21:
so 2,000
Aqual:
Yes
Aqual:
And I realized I'm dropping that won't, my bad
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Aqual:
Perimeter isn't necessary
AsleepAndUnafraid21:
oh ok
Aqual:
@aqual wrote:
And I realized I'm dropping that won't, my bad
Doing*
Aqual:
Wrong*
AsleepAndUnafraid21:
I belive i'm supposed to be using proportions but idk where to start
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Aqual:
Is angle cgr congruent to bpe
AsleepAndUnafraid21:
i think so
AsleepAndUnafraid21:
aren't they alternative interior angles?
Aqual:
so line segment cb is in the same position as line segment, or side, bp
AsleepAndUnafraid21:
yes
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Aqual:
so to find the change, you take side cb and divide the length by that of side bp
AsleepAndUnafraid21:
I'm confused. Is the person above me right?
Aqual:
yes
Aqual:
hold on
AsleepAndUnafraid21:
but i dont understand how pbc(a line segmen) is similar to an angle @surjithayer
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Aqual:
pbc is a triangle
Aqual:
or an angle
Aqual:
depending on how you write it
AsleepAndUnafraid21:
How? pbc is on the same line
surjithayer:
if we assume GRPC is a parallelogram.
Then triangles GCB and PEB are similar.
\[\frac{ GB }{ BE }=\frac{ GC}{ PE }=\frac{ CB }{ PB}\]
\[\frac{ 450 }{ BE }=\frac{ 400 }{ PE }=\frac{ 350 }{ 250 }\]
\[350BE=450 \times 250\]
\[BE=\frac{ 450\times250 }{ 350 }=\frac{ 2250 }{ 7 }=321\frac{ 3 }{7 }\]
\[350 PE=400\times 250=100,000\]
\[PE=\frac{ 100,000 }{ 350}=\frac{ 2000 }{ 7}=285\frac{ 5 }{ 7 }\]
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AsleepAndUnafraid21:
pbe is a triangle/angle
Aqual:
@asleepandunafraid21 wrote:
pbe is a triangle/angle
yes
Aqual:
so how i do it is i take the number the triangl;e is dilated by, here its 350/250, and i divide the other side lengths to find those of the triangle im trying to find
surjithayer:
it was a mis print ,now i have corrected.
thanks
AsleepAndUnafraid21:
that makes more sense
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Aqual:
so 350/250=1.4
so 450/1.4 should give you line be
Aqual:
400/1.4 should give you line pe
AsleepAndUnafraid21:
oh i think i get it
AsleepAndUnafraid21:
thank you @aqual @surjithayer
Aqual:
@surjithayer wrote:
if we assume GRPC is a parallelogram.
Then triangles GCB and PEB are similar.
\[\frac{ GB }{ BE }=\frac{ GC}{ PE }=\frac{ CB }{ PB}\]
\[\frac{ 450 }{ BE }=\frac{ 400 }{ PE }=\frac{ 350 }{ 250 }\]
\[350BE=450 \times 250\]
\[BE=\frac{ 450\times250 }{ 350 }=\frac{ 2250 }{ 7 }=321\frac{ 3 }{7 }\]
\[350 PE=400\times 250=100,000\]
\[PE=\frac{ 100,000 }{ 350}=\frac{ 2000 }{ 7}=285\frac{ 5 }{ 7 }\]
these are correct
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