A six-sided die of unknown bias is rolled 20 times, and the number 3 comes up 6 times. In the next three rounds (the die is rolled 20 times in each round), the number 3 comes up 6 times, 5 times, and 7 times. The experimental probability of rolling a 3 is %, which is approximately % more than its theoretical probability. (Round off your answers to the nearest integer.)
this die has a *bias* which means each side does *not* come up with equal probability. there are some side(s) that are favored over others. for the experimental probability of rolling a 3, divide (# of 3's rolled) / (#total # of rolls). convert to a percentage by multiplying by 100%. round to the nearest integer as stated by the problem. now, it asks you to compare this to the theoretical probability. on a *fair* die, the probability of getting a 3 would be 1/6 or 16.67% (rounded) now, it's asking how much more the experimental probability is compared to the theoretical one, so you'd subtract (the experimental probability) - (16.67%) and round the answer to the nearest integer.
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