how many positive two-digit numbers are evenly divisible by 4

Question

PG · Answer

HELP ME

Alexis1415 · Answer

" A number is divisible by 4 if and only if its last two digits (ten's place and one's place) are divisible by 4." The total numbers divisible by 4 is 22. Based on this quote you can solve it by seeing what it can go into.

surjithayer · Answer

first two digit number divisible by 4 is 12.
4)99(24
   96
 -

3
99-3=96
so last digit=96
sequence is 12,16,20,...,96
first term a=12
last term l=96
c.d. d=16-12=4
l=a+(n-1)d
96=12+(n-1)4
96-12=(n-1)4
84/4=n-1
n-1=21
n=21+1=22
total two digit terms divisible by 4=22