Mth help
@vocaloid
I tried 2x then +3
It wast ritgh, but i dont understand how else???
wasnt*
this stuff is child's play man what math class are you in?
?
review for precalc
what math are you taking in school
same, what grade?
are you going to help?
yeah, one min
2x and then 3 at the top (x+3) in the bottom first box (x-5) in the second
did that at the top of my head 😎
thats wrong
That is what i said in the beginning
those two literally sum together wth, show me how you're entering it
screenshot it
no, ive tried that with a question before i know what you're trying to do its wrong
thats literally how math works lol. 3/5 + 1/5 = 4/5. whats common, a common denominator
the top two are added together
Thats not right
one sec, ill show
see? those two equations add together to form the top one
(x-5)(x+3) = x^2-2x-15
yes ive tried that its wrong
i had a question similar and got it wrong
then the question is probably broken broski lol, or theres something in context that im not getting
is this from KA?
?
khan academy
go to msgs pls
sure
i got a 780 on SAT math so ive already graduated from this stuff lol, idk why its wrong
ive taken the act too, doesnt mean anything..?
what did you get on the ACT
converts to an SAT score lol
go to msgs so somone else can help idk how to use msgs
its in simplest form too which is weird
are you sure you're not missing anything
the expression can be simplified beyond that. let A and B be constants such that (2x+3)/(x^2-2x-15) = A/(x-5) + B/(x+3) multiply both sides by (x-5)(x+3) (2x+3) = A(x+3) + B(x-5) let x = -3 to eliminate the term with A and solve for B; likewise let x = 5 to solve for A. A and B should both be fractions which you can enter in the corresponding numerator and denominator blanks.
What do you mean "multiply both sides by (x-5)(x+3)"
both the demoninators ?
ok nvm i got it, thank you
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