Mathematics 58 Online
iosangel:

The general form of an parabola is 2x^2−12x−3y+12=0 What is the standard form of the parabola?

iosangel:

tis is what i got |dw:1665077161680:dw|

surjithayer:

$3y=2x^2-12x+12=2(x^2-6x)+12$ $3y=2(x^2-6x+9-9)+12$ $3y=2(x-3)^2-18+12$ $3y+6=2(x-3)^2$ $3(y+2)=2(x-3)^2$ $y+2=\frac{2}{3}(x-3)^2$

surjithayer:

you are correct