Question

The general form of an parabola is 2x^2−12x−3y+12=0

What is the standard form of the parabola?

Answer 1

tis is what i got

Answer 2

\[3y=2x^2-12x+12=2(x^2-6x)+12\]
\[3y=2(x^2-6x+9-9)+12\]
\[3y=2(x-3)^2-18+12\]
\[3y+6=2(x-3)^2\]
\[3(y+2)=2(x-3)^2\]
\[y+2=\frac{2}{3}(x-3)^2\]

Answer 3

you are correct