Question

Plz Help: What are the vertical asymptotes of the function f(x) = the quantity of 2x plus 8, all over x squared plus 5x plus 6?

x = −3 and x = −2
x = −3 and x = 2
x = 1 and x = −2
x = 1 and x = 2

Answer 1

For vertical asymptotes, you want to find values where the function is undefined. In our case, the function is undefined when the denominator = 0. you can factor the denominator and set each factor equal to 0 to find the x values that will be your asymptotes.

Answer 2

i dont get it how do you do that?

Answer 3

Review factoring when you get a chance.

x^2 + 5x + 6. Leading coefficient is 1, so factoring is simple. We pick two numbers that 1. Add up to the x coefficient, 5, and 2. Multiply to get the constant 6.

3 and 2 work.

Therefore your factors are (x+3)(x+2)

The denominator can now be written as (x+3)(x+2). The denominator is 0 when either x + 3 = 0 or x + 2 = 0 so you can solve these equations to get the two asymptotes.

Answer 4

Oh alright thank you

Answer 5

but thats not an answer :(

Answer 6

that gets you only positives which cant be

Answer 7

x + 3 = 0

Subtracting 3 from both sides gives us x = -3

Same logic for x + 2 = 0, subtract 2 to get x = -2

Answer 8

Oh i get it now. Thank you and im sorry for the stupidity