Write the equation of the line in fully simplified slope-intercept form.
First to start off you need to find your rise over run if the line goes up its positive if it goes down its negative you look at where the line crosses on the x-axis and for this one it crosses a -3, so not you will go up on the line because the line is going up. Once you find another point th goes in between you fine your run if you need more help lmk
Do you know how to get the equation in slope form to start off with . ?
my brain hurts lol
take any two points on the line. I take here (3,0) and (0,-3) \[slope ~m=\frac{ y _{2}-y _{1} }{ x _{2}-x _{1}}=\frac{ -3-0 }{ 0-3 }=\frac{ -3 }{ -3 }=1\] eq. of line is \[y-y _{1}=m(x _{2}-x _{1})\] y-0=1(x-3) y=x-3 which is the eq. of line in slope intercept form y=mx+c slope m=1 intercept c=-3
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