Question

Math

Answer 1

In which quadrants do solutions for the inequality y is less than or equal to two thirds times x minus 4 exist?

I, III, and IV
I, II, and III
I and IV
All four quadrants

Answer 2

All four quadrants

Answer 3

i got it wrong -_-

Answer 4

not jus you i asked like 5 people everyone said that so its whatever i got a 60 and its passing so im chilling

Answer 5

last time i did this test i got a 30%

Answer 6

i don't have to since it happened 💀

Answer 7

Do better 😂

Answer 8

The inequality \(y \leq \frac{2}{3}x - 4\) is in the form \(y \leq mx + b\), where \(m\) is the slope (\(\frac{2}{3}\)) and \(b\) is the y-intercept (\(-4\)).

In this case, because it's \(y \leq\), it means all the points below the line \(y = \frac{2}{3}x - 4\) satisfy the inequality. As you move down on the y-axis (from Quadrant I to Quadrant IV), the y-values decrease, and therefore, points in Quadrants III and IV satisfy the inequality \(y \leq \frac{2}{3}x - 4\). So it would’ve been (A), quadrant I, III, and IV