Ask your own question, for FREE!
Mathematics 20 Online
KarmaXD:

help as always-

KarmaXD:

toga:

@midnight97

toga:

I'm not great at reading graphs, but please tag me if it's not a graph.

toga:

@snowie

toga:

@toga wrote:
I'm not great at reading graphs, but please tag me if it's not a graph.
I broke my glasses.

Midnight97:

Sorry I ain't good with graphs

KarmaXD:

what about this

toga:

i will try

toga:

Using the distance formula, we can find the lengths of the sides of the triangle: AB = √[(5 - (-2))² + (-6 - 7)²] = √(7² + (-13)²) = √(49 + 169) = √218 AC = √[(5 - (-2))² + (7 - 7)²] = √(7² + 0²) = 7 BC = √[(5 - 5)² + (-6 - 7)²] = √(0² + 13²) = 13 Now, using the Pythagorean theorem, we have: AB² + BC² = AC² (√218)² + 13² = 7² 218 + 169 = 49 387 = 49 Since the equation 387 = 49 is not true, the given points do not form a right triangle. Therefore, we cannot apply the Pythagorean theorem in this case to find the value of c.

toga:

If I made a mistake, it's not entirely my fault. I broke my glasses and can't find my other pairs.

toga:

does this help

KarmaXD:

@toga wrote:
does this help
yes thank you!!

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!