Calculations (15 points) A Ferris wheel is an amusement park ride comprised of a large wheel rotating on an axis. There are cars or compartments where people can sit or stand that are evenly spaced about the circumference of the circle. The wheel rotates slowly, taking passengers on a ride around the circumference of the circle. Please select one of the following famous Ferris wheels: The Singapore Flyer has a diameter of 150 m and 28 compartments The London Eye has a diameter of 120 m with 32 compartments The Star of Nanchang has a diameter of 153 m and 60 compartments Report your research and complete the following calculation. Show all work for credit. 1. Name of the Ferris wheel 2. Diameter of the wheel (in meters) 3. Number of cars or compartments 4. Circumference of the wheel (in meters) 5. Area of the wheel (in meters) 6. Measure of a central angle in degrees 7. Arc length between two cars or compartments (in meters) 8. Area of a sector between two cars or compartments (in meters) Reflection (5 points) Answer the following questions. You must show all steps and provide any evidence needed in your solution to receive full credit. If a smaller replica of the Ferris wheel was constructed, what conclusions could you draw about the central angle of the original wheel and replica? Insert Answer Here What conclusions could you draw about the arc length of the original Ferris wheel and replica? Insert Answer Here Imagine the center of the Ferris wheel is located at (0, 0) on a coordinate grid, and the radius lies on the x-axis. Write an equation of a circle for your Ferris wheel. Insert Answer Here Part B Sketch an image of what your Ferris wheel would look like on the grid. (You can use Desmos to graph your equation or graph it on graph paper by hand) Insert Picture of Graph Here
The question is easy. But I aint gonna give the answer straight up.
Tell me what you know.
yeah
@toga
@oliver69
@manny300303199
offlline
No direct answers.
bro what
Against the rules.
Direct answers to questions posted are against the rules.
@acehuert
A Ferris wheel (also called a Giant Wheel or an observation wheel) is an amusement ride consisting of a rotating upright wheel with multiple passenger-carrying components (commonly referred to as passenger cars, cabins, tubs, gondolas, capsules, or pods) attached to the rim in such a way that as the wheel turns An amusement park ride consist of a large vertical cylinder that spins about its axis fast enough that any person inside is held up against the wall when the floor drop away. The coefficient of static friction between person and wall is μs, and the radius of the cylinder is R
okay
what kind of long math question is this..0-0
did u like copy and paste a test?
its geometry
its not a test its a assignment
does no one know it </3
If a smaller replica of the Ferris wheel was constructed, the central angle of the original wheel and replica would remain the same. The central angle is determined by the number of compartments on the wheel and is not affected by the size of the wheel. The arc length of the original Ferris wheel and replica would change proportionally to the size of the wheel. A smaller replica would have a smaller arc length between two compartments compared to the original wheel.
which could mean what?
or, what would the equation of the circle for The Star of Nanchang Ferris wheel be?
@umamsmaiaud Did you at least do 1-3? Those are pretty self-explanatory..
yeah ofc
Okay, which of the 3 wheels did you pick? I can help you from there
the third one the star one
🧢
Okay, so the Star of Nanchang has a diameter of 153 m. The circumference formula is \(\large C=2\pi r \) To find radius, we need to take half of the diameter. \[\large \frac{153m}{2} =r\] Then plug that into the formula to get the C
okay
Did you get an answer? So we could move on to the next one
um no
Well.. online calculators exist if you don't have a physical one: https://www.desmos.com/scientific But anyways, plugging it in, you get \(\large C= 480.66 m \) So, \(\color{yellow}{4) 480.66~m}\) Moving on to 5, area is pretty straight forward: \[\large A= \pi * (\frac{153}{2} )^2 \]
A=23409π/4
Yes, which, when simplified is just 18,385.39 meters. So that would be #5 For 6, to find the central angle measures, we need the number of compartments. Which is given as 60. The degrees of a circle are 360, so just divide the angle with the amount of compartments in the wheel: \[CA(central~angle)=\large \frac{360}{60}=? \]
6
Yes, now, 7 is gonna be a bit long. To find the arc length, you are gonna need the central angle measure. \(\color{red}{6} \), and the radius, \(\large \color{red}{\frac{153}{2}} \). The arc length formula is this: \[\Large S= 2*\pi*r*(\frac{\theta}{360})\] Where \(\theta\)= central angle measure and r=radius \[\Large S= 2*\pi*(\frac{153}{2})*(\frac{6}{360}) \]
Area of a sector (#8) will be similar, being just: \[\Large A= \frac{\theta}{360}*\pi*r^2 \] Hopefully you understand it, good luck!
is that just the answer?
After you plug in the values and calculate, you will get the answers.
Please close this question.
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