im cooked arent i
The height h in feet of an object shot straight up with initial velocity v in feet per second is given by h = −16t2 + vt + c, where c is the initial height of the object above the ground. A model rocket is shot vertically up from a height of 6 feet above the ground with an initial velocity of 22 feet per second. Will it reach a height of 10 feet? Identify the correct explanation for your answer.

Question

Yanaisswaggy · Answer

i got a brain ingury reading this

Yanaisswaggy · Answer

butttttt

Yanaisswaggy · Answer

c = 4 ft
v = 48 ft/s
 
We want to know if the height will be 40 at a certain time t.
 
h = 40
 
Plug in these values of c, v, and h into the equation.
 
40 = -16t2 + 48t + 4

Subtract 40 on both sides of equation.
 
0 = -16t2 + 48t - 36

We can factor out the 2 on the right side of the equation to simplify it.
 
h = 2(-8t2 + 24t + 13)

The discriminant is the square-root part of the quadratic formula.  The value under the square-root is
 
b2 - 4ac
 
where:
a = -8
b = 24
c = 13
 
242 - 4(-8)(13) =
576 + 416 =
992
 
The value under the square-root is positive.  Therefore, when we solve for t, we will have a real value of time.  In conclusion, the object will reach a height of 40 ft when we solve for that time.

NaiNoah · Answer

@yanaisswaggy wrote:

c = 4 ft v = 48 ft/s We want to know if the height will be 40 at a certain time t. h = 40 Plug in these values of c, v, and h into the equation. 40 = -16t2 + 48t + 4 Subtract 40 on both sides of equation. 0 = -16t2 + 48t - 36 We can factor out the 2 on the right side of the equation to simplify it. h = 2(-8t2 + 24t + 13) The discriminant is the square-root part of the quadratic formula. The value under the square-root is b2 - 4ac where: a = -8 b = 24 c = 13 242 - 4(-8)(13) = 576 + 416 = 992 The value under the square-root is positive. Therefore, when we solve for t, we will have a real value of time. In conclusion, the object will reach a height of 40 ft when we solve for that time.

then tell me this No; The discriminant is negative, so the rocket will not reach a height of 10 feet. Yes; The discriminant is zero, so the rocket will reach a height of 10 feet. Yes; The discriminant is positive, so the rocket will reach a height of 10 feet. No; The discriminant is positive so the rocket will reach a height of 10 feet. these are the option choices

Yanaisswaggy · Answer

pretty sure its no, but not 100% sure

NaiNoah · Answer

@yanaisswaggy wrote:

pretty sure its no, but not 100% sure

my grade depends on you, ill let yk when I get the grade back

Yanaisswaggy · Answer

OMG

Yanaisswaggy · Answer

ur stupid

Yanaisswaggy · Answer

im not smart

Yanaisswaggy · Answer

but i tried my best

NaiNoah · Answer

@yanaisswaggy wrote:

but i tried my best

if I fail my grade goes from a A to a B

Yanaisswaggy · Answer

omg

Yanaisswaggy · Answer

im so sorry if its bad

Yanaisswaggy · Answer

im going to kill myself if its bad

NaiNoah · Answer

@yanaisswaggy wrote:

im going to kill myself if its bad

don't say that lmao

Yanaisswaggy · Answer

its finna be my fault

NaiNoah · Answer

@yanaisswaggy wrote:

its finna be my fault

it'll be fine

Yanaisswaggy · Answer

:\

velmalovesshaggy145 · Answer

projectile motion?

velmalovesshaggy145 · Answer

parametric equations?

NaiNoah · Answer

@velmalovesshaggy145 wrote:

parametric equations?

The Discriminant

velmalovesshaggy145 · Answer

oh its a similar concept i believe.

surjithayer · Answer

$$h=-16t^2+22t+6$$
when h=10 ft
$$-16t^2+22t+6=10$$
$$-16t^2+22t-4=0$$
divide by -2
$$8t^2-11t+2=0$$
$$discriminant=(-11)^2-4\times 8 \times2=121-64=57>0$$
so roots are real
Hence it can reach 10 ft above the ground.