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I need help QwQ
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@oliver69 can u help me on this
Okay so for the first image it is (6c)^2(4c)^3 =2304c^5 Bascially you do 6c times 6c twice and then 4c time 4c three times Then you add the exponets, then multiple the products, and you will get 2304c to the power of 5
Simplified?
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@breathless wrote:
Simplified?
dam
@breathless wrote:
dam
yeah based on that image I just did exactlty what it asked for
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Yesh now the other one QwQ
fractions PwP
Okay gimme a second and I'll help with that one
Oki
\[(\frac{ 2 }{ 9 }a ^{3})^2(\frac{ 2 }{ 7} a^2)^2 =\frac{ 16 }{ 3969 }a^9\] You add up the exponents. Then combine the like terms and multplie and such the fractions, and yes it's simplified
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Crazy
@oliver69 wrote:
\[(\frac{ 2 }{ 9 }a ^{3})^2(\frac{ 2 }{ 7} a^2)^2 =\frac{ 16 }{ 3969 }a^9\]
You add up the exponents. Then combine the like terms and multplie and such the fractions, and yes it's simplified
-v-
@breathless wrote:
@oliver69 wrote:
\[(\frac{ 2 }{ 9 }a ^{3})^2(\frac{ 2 }{ 7} a^2)^2 =\frac{ 16 }{ 3969 }a^9\]
You add up the exponents. Then combine the like terms and multplie and such the fractions, and yes it's simplified
You got the point though
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yesh Thank you that's all I need ^^
Glad I could help
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