Question

Can someone help me solve this equation step by step b/b-5-2/b+5=50/b^2-25

Answer 1

Please provide this equation as a screenshot 🙏

Answer 2

To solve the equation b/(b-5) - 2/(b+5) = 50/(b^2-25):
Find a common denominator for all fractions involved: (b-5)(b+5).
Rewrite each fraction with this common denominator.
Simplify to get the equation in terms of ‘𝑏’.
Multiply through by ((five-B))10 to eliminate denominators. The resulting quadratic equation is: FifteenB^2+Fifty-five*B-Thirty=Zero 6.Solve using factoring or applying the quadratic formula.
The solutions are {b= 5, 60}

Answer 3

that should be right Ngl

Answer 4

Following what Kasy did, multiply by a common denominator: \( (b-5)(b+5) = (b^2-25) \)

You end up with:
\(\large \frac{ b[(b-5)(b+5)] }{b-5} - \frac{2[(b-5)(b+5)] }{b+5} = \frac{50 [(b-5)(b+5)]}{(b-5)(b+5)} \)

Cancel out like terms and you're left with:
\(\large b(b+5) -2(b-5) =50 \)

Distribute and combine like terms:
\(\large b^2+5b-2b+10 =50 \)

\(\large b^2+3b+10 =50 \)

\(\large b^2+3b -40=0 \)

Now just factor, if possible:
\(\large (b+8)(b-5) =0 \)

You end up with the two equations; \(\large b+8=0 \) and \(\large b-5=0 \)

Answer 5

I got -8 😭