Question

;-; exam is next tuesday, and i dont get a single thing (well maybe one or two) can someone helppp

Answer 1

Yeah, I can try to help. Let me teach myself first lol

Answer 2

Oh, alr then!

Answer 3

So I google imaged it... it said Simplified expressions are 1, 2 csc x, -1 and cos ^2x.
But that doesn't make sense... for the first question are you supposed to simplify all of them?

Answer 4

Oh wait... Simplify each trigonometric expression using trigonometric identities.

Answer 5

Step 1: 1+cot^2x=1/sin^2x
sin^2x(1+cot^2x) = sin^2x times 1/siin^2x
sin^2x(1+cot^2x)=1

Step 2: Find a common denominator and add the fractions.
1-cosx/sinx + sinx/1-cosx = (1-cos x)^2 +sin^2x/sin x(1-cosx)
Expand and simplify the numerator:
I wish I didn't start doing this...
(1-2cosx+cos^2x)+sin^2 x/ sinx(1-cosx)
1-2csx+(cos^2x+sin^2x)/sinx(1-cosx)
Use the identity sin^2x+cos^2x=1:
1-2cosx+1/sinx(1-cosx)=2-2cosx/sinx(1-cosx)
Factor and simplify:
2(1-cosx)/sinx(1-cosx)= 2/sin x
Use the identity csc x= 1/sinx:
2/sinx=2cscx
Step 3:
Use the identity 1+tan^2x=sec^2x:
tan^2x-sec^2c=tan^2x-(1+tan^2x)
step 4:
Simplify: 2+tan^2x/sec^2x - 1
Solution: simplified solutions are:
1,2 cscx, -1 and cos^2x


I hate myself now... lol

Answer 6

I really hope that helps because I spent like too much time on that...

Answer 7

Shoot... that was only the first question... NOOOOOOOOOOOOOOOOOOOOOOOOOOOOOO!!!

Answer 8

You might have to use PEMDAS in some of the problems, but idk though...

Answer 9

ur scaring me with numbers...

Answer 10

I'M GOING CRAZY!!!

Answer 11

srry im backk lol yeah ik im going crazy with this too, and i got taught by an actual college professor who only talks and talks and talks

Answer 12

Sounds like my geometry teacher, lol