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1,200 employees of a company were surveyed to find out whether they were satisfied with the company’s insurance policy. The survey showed that 80% of the respondents were not satisfied with the policy. The standard error of the proportion is %. The number of people who are satisfied with the policy is between % and %.
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You're missing some information. The standard error is defined as \(\Large SE = \frac{\sigma}{\sqrt{n}} \) But in order to find \(\sigma\) we need the original data (x) and the mean. \(\large \sigma = \sqrt{\frac{\sum (x_i-x)^2}{n-1}} \)
the standard error of the proportion is like 1.16%.
@caspianwilde wrote:
the standard error of the proportion is like 1.16%.
@mintyy wrote:
@caspianwilde wrote:
the standard error of the proportion is like 1.16%.
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