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If x โ 0 and y โ 0, then 2๐ฅ y รท 6๐ฆ x someone teach me how to solve it...I don't want the answer, I want to learn how to solve it
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its supposed to be: if X=0 and xโ 0 then 2x/y divided by 6y/x
Im not sure I did this right but: x^2/3y^2 ?๐คท I haven't done this is a while
I don't want the answer I want the way you used to solve it, like how did you get that answer
Oh ok. So first rewrite the division as multiplication. So I would be: 2x/ times by 6y/x. Then you multiply the fractions and you should get 2x^2//6y^2. But simplify that and you get x^2/3y^2
@luna34 wrote:
Oh ok. So first rewrite the division as multiplication. So I would be: 2x/ times by 6y/x.
Then you multiply the fractions and you should get 2x^2//6y^2. But simplify that and you get x^2/3y^2
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ofc!
@luna34 wrote:
ofc!
@maxton wrote:
@luna34 wrote:
ofc!
@luna34 wrote:
@maxton wrote:
@luna34 wrote:
ofc!
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