Question

What is x 3+y 3+z 3=k

Answer 1

I can;t figure it out I need help

Answer 2

Thank you

Answer 3

\(x=\sqrt[3]{k-y^{3}-z^{3}}\)

Answer 4

My teacher isn't good at helping so thank you

Answer 5

Step \(x^{3}+y^{3}+z^{3}=k\)\(\xpmhighlightbox{bgcolor=#3A3F50, underlinecolor=#3A3F50}{x^{3}+y^{3}+z^{3}}=k\)Move the variables to the right-hand side and change their signs \(x^{3}=\xpmhighlightbox{bgcolor=#3A3F50, underlinecolor=#3A3F50}{-y^{3}-z^{3}}+k\)Step \(x^{3}=-y^{3}-z^{3}+k\)\(\xpmhighlightbox{bgcolor=#3A3F50, underlinecolor=#3A3F50}{x^{3}}=\xpmhighlightbox{bgcolor=#3A3F50, underlinecolor=#3A3F50}{-y^{3}-z^{3}+k}\)Take the root of both sides of the equation \(\xpmhighlightbox{bgcolor=#3A3F50, underlinecolor=#3A3F50}{x}=\xpmhighlightbox{bgcolor=#3A3F50, underlinecolor=#3A3F50}{\sqrt[3]{-y^{3}-z^{3}+k}}\)Step \(x=\sqrt[3]{-y^{3}-z^{3}+k}\)\(x=\sqrt[3]{\xpmhighlightbox{bgcolor=#3A3F50, underlinecolor=#3A3F50}{-y^{3}-z^{3}+k}}\)Use the commutative property to reorder the terms\(x=\sqrt[3]{\xpmhighlightbox{bgcolor=#3A3F50, underlinecolor=#3A3F50}{k-y^{3}-z^{3}}}\)Solution\(x=\sqrt[3]{k-y^{3}-z^{3}}\)

Answer 6

Thank you Nina