An Algebra 2 question that I want to see if I got correct:

Question

tax · Answer

$$5x^{2/3} + 14 = 59$$

And my final answer was: $$x = 27$$

Is this correct? @xxaikoxx

tax · Answer

Because I know that there was a point in the problem where you had to find the reciprocal of the fraction as well, so my answer that I got depends on how I did those steps

tax · Answer

@xxaikoxx Here

xXAikoXx · Answer

@tax wrote:

$$5x^{2/3} + 14 = 59$$ And my final answer was: $$x = 27$$ Is this correct? @xxaikoxx

Unfortunately, your answer is not correct. Here's why: Subtract from both sides here $$\frac{ 5x^2}{3} = 45$$ Then multiply both sides by 3 $$5x^2 = 135$$ Next, divide by 5 $$x^2 = 27$$ 4. Now we take the square root $$x=±\sqrt{27} =±3\sqrt{3} $$ Therefore, x = 27 is NOT true because it is the answer to $$x^2$$ Instead, ** x = 3. ** This will right.

tax · Answer

@xxaikoxx wrote:

@tax wrote:

$$5x^{2/3} + 14 = 59$$ And my final answer was: $$x = 27$$ Is this correct? @xxaikoxx

Unfortunately, your answer is not correct. Here's why: Subtract from both sides here $$\frac{ 5x^2}{3} = 45$$ Then multiply both sides by 3 $$5x^2 = 135$$ Next, divide by 5 $$x^2 = 27$$ 4. Now we take the square root $$x=±\sqrt{27} =±3\sqrt{3} $$ Therefore, x = 27 is NOT true because it is the answer to $$x^2$$ Instead, ** x = 3. ** This will right.

Yay, thank you!

tax · Answer

I have like 4 more by the way :sob: