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( a-b)^2 ≠ 4^2 + 5^2
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$$(a+b)^2≠4^2 + 5^2$$
try expanding the Left-hand-side first. so the equation in terms of variables is:
$$(a+b)^2 \neq (a)^2 + (b)^2 $$
In particular, this is because:
$$(a + b)^2 = (a + b)(a + b)$$
Which evaluates to something very different than $$a^2 + b^2$$.
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