OpenStudy (anonymous):

How do you write the equation of the line parallel to y=3x-1 that passes through the point (-3, -5)?

7 years ago
OpenStudy (anonymous):

parallel means identical slopes, so m=3, and using pt-slope form, Y-Y1=m(x-x1), the parallel line is Y+5=3(X+3) so Y=3X+9-5 So........................Y=3X+4 Y=3X+4 is the eqtn.

7 years ago
OpenStudy (anonymous):

Wow. Dude can um you explain that to me?

7 years ago
You are given one function, which is $$y = 3x - 1$$. This tells you that the slope for the second line must be 3 in order for it to be parallel. The only thing you have left to find out then is the y-intercept that will let the line go through the point (-3, -5). A point is a pair, (x, y) that gives you an X value and Y value that are on the line. Since you have m, you can say: $$y = 3x + b$$ $$(-5) = 3 \cdot (-3) + b$$ Here we plugged in the point that we want to be on the line -- (-3, -5) -- into our equation. Then, we can solve for b: $$-5 - (3 \cdot (-3)) = b$$ This will give us the value of b, which we can then plug back into the equation: $$y = 3x + (-5 - (3 \cdot (-3)))$$