Question

6x^(6) + 8x^(4) - 15x^(3) - 20x

Answer 1

if you look at the exponents on each term, you notice the first two are even and the last two are odd. you will need to incorporate a grouping strategy.

first factor out the great common factor of each of the first two terms of coefficients and then factor out the lowest factor of x of the first two terms also, you should be left with a linear (or nearly linear factor)

\[6x^{6} + 8x^{4}\]
what is the greatest common factor of 6 and 8?
what is the lowest factor of those exponents?
what are you left over with?

Answer 2

you do the same with \[-15x^{3} - 20x\]

Answer 3

gcf 48

Answer 4

oops i meant least common factor* sorry!

Answer 5

ok so what is the least common multiple*** of 6 and 8?

Answer 6

tht would be 24

Answer 7

dude let her figure it out

Answer 8

oh sorry
my bad

Answer 9

robot and toast

Answer 10

ok shirl...ignore what i said up there about the greatest common factor or whatever...

what is the least common multiple of 6 and 8?

Answer 11

what is going on here

Answer 12

24

Answer 13

good job shirl

Answer 14

what is mathpath

Answer 15

ok no least common multiple...i.e.. a factor of 6 and 8

Answer 16

dude thats not even the correct answer so shes wrong

Answer 17

r u sure

Answer 18

ok the least common multiple of 6 and 8 is 2

why?

because you can factor out a 2 from 6 and 8

Answer 19

it is the name of my organization

Answer 20

how can 2 be a multiple of 6 and 8

Answer 21

i meant factor

Answer 22

oh ok i was wondering........

Answer 23

are you going to help me

Answer 24

ok so now look at the exponents of x

\[x^{6} and x^{4}\]

which one is lower?

Answer 25

i think she left dude

Answer 26

i'm trying to help you...

ok here's a question:

can you factor x^4 from x^6 ?
answer: yes because x^4(x^2) = x^6 so what you do with the first two terms is factor out the lowest exponent and greatest common factor*** from the ones with the even terms

you get : 2x^4 (3x^2 +4) -5x(3x^2 + 4)

now if you look at this what do you see in common between the odd and even exponents that were not there before? the factor (3x^2 + 4)
now because you are using the grouping idea you can also group the 2x^4 and the -5x. then you can factor (2x^4 - 5x) to x(2x-5)

the final answer is x(3x^2 +4)(2x-5)

Answer 27

u explained well robots! ;)

Answer 28

thanks...if that doesn't make sense then i can try to explain it again

Answer 29

well it made sense to me atleast!