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OpenStudy (anonymous):

what is the solution? 2m^2+7m-22<0

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OpenStudy (anonymous):

first, you should graph this function, then, you can use the quadratic equation to solve for m

OpenStudy (anonymous):

m is just a variable. It might be easier to replace m with x and then graph it on the xy plane

OpenStudy (anonymous):

\[x = ( -b \pm \sqrt{b^2 - 4*a*c})/(2*a)\]

OpenStudy (anonymous):

Whenever you see "<" or ">" you can treat it as an equal sign. After you get the graph down the < let's you know what part is shaded. (below or above the line) I'm getting m = 2 or m = -11/2

OpenStudy (anonymous):

"a" is coeffecient on x^2, "b" is the coeffecient on x term, "c" is the term with no x ... => a*x^2 + b*x + c

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OpenStudy (anonymous):

8/4 or -22/4..right

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