find the coordinates of the vertex, zeros, sketch: f(x)=x^2+x-6
for algebra .....vertex is -b/2a and zeros will be...factor and set equal to zero and solve for x
for this function a=1, b=1 and c=-6....just the coefficients so vertex will be -1/2(1) or -1/2. factoring this function (x+3)(x-2)=0 then using zero product property x=-3 and x=2 which are the zeros!!!
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