Question

How do you solve this problem for X: -3(x+1)-x/2+3/2<0

Answer 1

you distribute the -3, and add like terms...you solve it like you would if the less than sign is an equal sign

Answer 2

only difference is if you divide or multiply by a negative you change the sign...so in this case you would change it to a greater than sign if you divide or multiply by a negative

Answer 3

ok what terms do you distribute the -3 to?

Answer 4

just -3(x+1) since the -3 is in front of that parenthesis

Answer 5

ok so it would be 3x+3?

Answer 6

but there is a negative...so u distribute the - as well, -3x-3

Answer 7

so then it would look like this them -3x-3-x/2+3/2<0 ?

Answer 8

yup

Answer 9

yup

Answer 10

add like terms...keep all the x's on one side of the inequality and everything else on the other

Answer 11

ok so like this -3x+x/2<0-3+3/2?

Answer 12

you should be adding 3 to both sides , not subtracting

Answer 13

so it should be -3x-x/2<3-3/2

Answer 14

so it would look like this -3/2x<1.5?

Answer 15

how would you evaluate -3-1/2? having the x is the same thing. if it would be easier for you to get rid of the fraction, you could multiple the whole inequality by 2 to get rid of the fractions

Answer 16

ok i just get how to even do these and you are making me even moe confused.

Answer 17

oh sorry...i'm trying to explain it to you instead of just giving you the answers

Answer 18

on the left side of the inequality we have -3x-x/2, right?

Answer 19

the x in x/2 can also be written as (1/2)x. let's change that to a decimal so it's easier to work with...(1/2)x is also 0.5x. So we have -3x-0.5x which equals -3.5x.

Answer 20

so now you should have -3.5x<1.5

Answer 21

now to solve for x, you would just divide both sides by -3.5, which will change the inequality sign to >