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OpenStudy (anonymous):

Find the productof (x^2-3x+2) with the quotient (6x^6-9x^5-3x^3)/ 3x^3? Can anyone explain how to do this?

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OpenStudy (anonymous):

Simplify the quotient by dividing out 3x^3. Then just expand the brackets

OpenStudy (anonymous):

It's very simple friend..... quotient= (6x^6-9x^5-3x^3)/3x^3=2x^3-3x^2-1) & now simply multiply it with (x^2 3x +2)

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