Question

I'm having trouble...I have to factor n^2 + n + 16...

Answer 1

Well
that expression alone is a prime factor within the Real numbers set.

Answer 2

Tho in the Complex set it has this two factors: \[n ^{2}+n+16=\left( n+0.5\left( 1+\sqrt{-47} \right) \right)\left( n+0.5\left( 1-\sqrt{-47} \right) \right)\]

Answer 3

.... which are found by use of the quadratic formula

Answer 4

Depending on the type or problem, you'll just want to use the "completing the square" method, and just create a perfect factor.