Ask your own question, for FREE!
Mathematics 13 Online
OpenStudy (anonymous):

I am having trouble with exponents, can anyone help? (2m^2q^-1)^3(mx)^-1 -------------------- (8qx^1/2)^2

OpenStudy (anonymous):

So, you have \[(2m^2q^{-1})^3(mx)^{-1} \over (8qx^{1/2})^2\] We have to simplify this. When you have exponent in the form \[(a^n)^m\] you can rewrite this as \[a^{nm}\] (and vice versa of course). This gives us simpler expression: \[(8m^6q^{-3})(mx)^{-1} \over x(8q)^2\] We can simplify better because we have negative exponents. Negative exponents have the following property: \[a^{-n} = {1 \over a^n}\] Now, move negative exponents from numerator to denominator: \[8m^6 \over mq^3x^2(8q)^2\] So, we got rid off negative exponents. Now, notice that we have \[m\] in numerator and denominator, \[{a^n over a^m} = a^{n-m}\] So, we get: \[8m^5 \over q^3x^2(8q)^2\] You've probably noticed that we have here untouched \[(8q)^2\] We have to use this property now: \[a^n * a^m = a^{n+m}\] and this gives us: \[8m^5 \over 64x^2q^5\] Now, divide by 8: \[m^5 \over 8x^2q^5\]

OpenStudy (anonymous):

Lovely explanation, but YOU did all the work.

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Latest Questions
AsianPanda08: What should i eat for dinner tonight? I can't choose
1 hour ago 51 Replies 2 Medals
Nina001: Trying 2 figure out what is the square root of 8746685
1 second ago 29 Replies 2 Medals
SnowyBreaks: Is it bad to lose 3.8 pounds in less than 2 days?
30 minutes ago 43 Replies 0 Medals
kaelynw: tried a lil smt, the arm is off but i like the other stuff
11 minutes ago 10 Replies 2 Medals
laylasnii13: Who wanna write or make a song with me???
4 hours ago 8 Replies 0 Medals
kaelynw: art igg
13 hours ago 13 Replies 2 Medals
XShawtyX: Art
1 day ago 6 Replies 0 Medals
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!