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Mathematics 65 Online
OpenStudy (anonymous):

Two boats leave a port at the same time, one going north and other traveling south. The northbound boat travles 16 mph faster than the southbound boat. If the southbound boat is traveling at 47 mph, how long will it be before they are 1430 miles apart?

OpenStudy (anonymous):

r u in geometry

OpenStudy (anonymous):

No i am im in elementry algerbra

OpenStudy (anonymous):

can you help me with this, its a little confusing

OpenStudy (anonymous):

i know i have tried to solve it many times let me keep trying

OpenStudy (anonymous):

r u still there

OpenStudy (anonymous):

hello?

OpenStudy (anonymous):

i have the answer

OpenStudy (anonymous):

Yeah I am here sorry, How did you do it?

OpenStudy (anonymous):

okay so the first thing you want to do is compare the two and make a relationship

OpenStudy (anonymous):

there are two things that the boats have in common the the rate unit and the distance right

OpenStudy (anonymous):

Right!

OpenStudy (anonymous):

so the formula that ties speed, time, and distance is d=st

OpenStudy (anonymous):

right

OpenStudy (anonymous):

distance = speed times time

OpenStudy (anonymous):

yeah, I forgot to put the formula

OpenStudy (anonymous):

time can also be represented as a rate in this case we have mph

OpenStudy (anonymous):

Okay so would you now set the equation up

OpenStudy (anonymous):

therefore it would be appropriate to say distance= speed times rate

OpenStudy (anonymous):

so one boat is going x mph the other boat is going 16+x

OpenStudy (anonymous):

x=47 and 16+47 is 63

OpenStudy (anonymous):

the only thing that ties these two boats together is the distance so we can assume the equation will be equal to 1430 or the distance

OpenStudy (anonymous):

right

OpenStudy (anonymous):

Yes that true!

OpenStudy (anonymous):

the other side would be related because it shares a common unit the rate or mph

OpenStudy (anonymous):

therefore 1430=rt+rt

OpenStudy (anonymous):

the rates are 63 mph and 47 mph

OpenStudy (anonymous):

t = time

OpenStudy (anonymous):

so the final equation looks like 1430=63t+ 47t

OpenStudy (anonymous):

1430=110t

OpenStudy (anonymous):

1430/110=t

OpenStudy (anonymous):

Its would be 13!

OpenStudy (anonymous):

Thanks Dude!

OpenStudy (anonymous):

it would be 13 hours

OpenStudy (anonymous):

yes, your welcome if you have any other questions i can help

OpenStudy (anonymous):

Okay Well that was my last problem though But if I have anymore question I will ask away!

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