Two boats leave a port at the same time, one going north and other traveling south. The northbound boat travles 16 mph faster than the southbound boat. If the southbound boat is traveling at 47 mph, how long will it be before they are 1430 miles apart?

r u in geometry

No i am im in elementry algerbra

can you help me with this, its a little confusing

i know i have tried to solve it many times let me keep trying

r u still there

hello?

i have the answer

Yeah I am here sorry, How did you do it?

okay so the first thing you want to do is compare the two and make a relationship

there are two things that the boats have in common the the rate unit and the distance right

Right!

so the formula that ties speed, time, and distance is d=st

right

distance = speed times time

yeah, I forgot to put the formula

time can also be represented as a rate in this case we have mph

Okay so would you now set the equation up

therefore it would be appropriate to say distance= speed times rate

so one boat is going x mph the other boat is going 16+x

x=47 and 16+47 is 63

the only thing that ties these two boats together is the distance so we can assume the equation will be equal to 1430 or the distance

right

Yes that true!

the other side would be related because it shares a common unit the rate or mph

therefore 1430=rt+rt

the rates are 63 mph and 47 mph

t = time

so the final equation looks like 1430=63t+ 47t

1430=110t

1430/110=t

Its would be 13!

Thanks Dude!

it would be 13 hours

yes, your welcome if you have any other questions i can help

Okay Well that was my last problem though But if I have anymore question I will ask away!

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