Question

d=square root of (square root 2 -5 sr 2)^2 +(- sr 3 - seven sr 3)^2

Answer 1

all right. the equations is.

\[d = \sqrt{2 - 5 \sqrt{2}} + (-\sqrt{3} - 7 * \sqrt{3})^2\]

Answer 2

is that right?

Answer 3

well, the 1st sr is over the whole problem....

Answer 4

nm.....duh

Answer 5

I've been doing this hw since yesterday, I'm in a dark zone....I am just feed up with gettin to a prob. then stuck, which thats been all 87 prob.

Answer 6

sorry can you try rewriting the problem

Answer 7

there are a lot of sqrt's and I can't tell which numbers of grouped under square roots and not, o_0...

Answer 8

\[ d=\sqrt (\sqrt 2-5\sqrt2)^2+(-\sqrt 3 -7\sqrt3)^2\]

Answer 9

It sqrt's the whole equation.... make sence? I hope

Answer 10

ok

Answer 11

so, let's start with each paranthetical group, focusing on the left one with root(2)

Answer 12

can you evaluate \[\sqrt{2} - 5\sqrt{2}\]

Answer 13

got lost...yep

Answer 14

-4\[-4\sqrt 2\]

Answer 15

now square it

Answer 16

\[-8\sqrt3\]

Answer 17

thats where I'm lost....how do you ^2 a sqrt?

Answer 18

ok, so a square root is just this: you have a number, x, that you multiply by itself, x * x, to yield another value, x*x = y, so the square root of y is x.

Answer 19

\[do you 16*2 then ^2 or do you ^ the 4 and the 2 separate?\]

Answer 20

square root of 2 is actually a value less than two. if you have multiply \[\sqrt{2} * \sqrt{2}\] you'll get 2

Answer 21

so in that case you had, y = x*x, so the square root of y is x, here you could say that y =2, therefore x = \[\sqrt{2}\]

Answer 22

so you get 16 * 2 then square?

Answer 23

16 *2 is the result of \[-4\sqrt{?}\] sqaured

Answer 24

sorry, that ? is a 2

Answer 25

i'm confused as to why you square it again?

Answer 26

you've solved the left paranthetical group, so solve the right

Answer 27

\[d=\sqrt (x2 -x1)^2 +(y2-y1)^2\] right?

Answer 28

this is the distance equation, yes

Answer 29

did you solve the problem?

Answer 30

1024+36864 right?

Answer 31

sqrt? right?

Answer 32

so you have 16*2 on the left and what on the right? i get 64 * 3 on the right

Answer 33

so that is 16*2 + 64*3

Answer 34

squareroot( 16 *2 + 64*3 ), unless there are other operations missing in the original equation...

Answer 35

Sorry! I keep gettin stuck with trin to post my comments to you!! I got 1024 + 36864 then sqrt 37288? am I right so far?

Answer 36

i think the numbers you have are way too big, how did you get 1024?

Answer 37

I squared the 16*2 and 64*3....?

Answer 38

Are you still with me? If not then thanx for all your help...if you are then am I right or wher am I going wrong?

Answer 39

why did you square them?

Answer 40

you already did, that's how you have 16*2 and not -4*sqrt(2)

Answer 41

look at the prob again.....in th () you have to get the sqrt down to be squared...

Answer 42

If not then how do you ^ 2 a sqrt?

Answer 43

a sqrt is just a number that if you square that number, you get another number...so if you have \[\sqrt{2}\], if you square that you get 2. if you "^2 a sqrt" those two operations are cancelling eachother out...so you did this when you found that

Answer 44

\[(-4*\sqrt{2})^2 = 16 * 2\]

Answer 45

right there you squared a square root

Answer 46

oh, ok....

Answer 47

rt(2) squared is 2

Answer 48

so how do I do the -8 sqrt 3 ^2?

Answer 49

the same way as you did with the left, ;)

so what is -8 squared?

Answer 50

64

Answer 51

what is \[\sqrt{3}\] squared?

Answer 52

3?

Answer 53

right

Answer 54

so you have 16*2 + 64*3

Answer 55

so i sqrt 160?

Answer 56

you have 32 + 192

Answer 57

that is the value you square root

Answer 58

the 32 is negative?

Answer 59

no.....

Answer 60

both value are positive, they were calculated from negative values that you then squared, and when you multiply two negative numbers you get a positive

Answer 61

So d=14.96?

Answer 62

right, \[\sqrt{204}\]

Answer 63

So you are in Georgia IT?

Answer 64

sorry, that wwas poor adding

Answer 65

\[\sqrt{224}\]

Answer 66

yes, i am

Answer 67

was this helpful?

Answer 68

where are you from?

Answer 69

Great Help!! Thanx more than you'll ever know!! Good ol' Tennessee

Answer 70

right on, no problem, :)

Answer 71

Maybe you can help me again soon!! God Bless!

Answer 72

of course, would be glad too

Answer 73

thanks