Mathematics 48 Online OpenStudy (anonymous):

d=square root of (square root 2 -5 sr 2)^2 +(- sr 3 - seven sr 3)^2 OpenStudy (anonymous):

all right. the equations is. $d = \sqrt{2 - 5 \sqrt{2}} + (-\sqrt{3} - 7 * \sqrt{3})^2$ OpenStudy (anonymous):

is that right? OpenStudy (anonymous):

well, the 1st sr is over the whole problem.... OpenStudy (anonymous):

nm.....duh OpenStudy (anonymous):

I've been doing this hw since yesterday, I'm in a dark zone....I am just feed up with gettin to a prob. then stuck, which thats been all 87 prob. OpenStudy (anonymous):

sorry can you try rewriting the problem OpenStudy (anonymous):

there are a lot of sqrt's and I can't tell which numbers of grouped under square roots and not, o_0... OpenStudy (anonymous):

$d=\sqrt (\sqrt 2-5\sqrt2)^2+(-\sqrt 3 -7\sqrt3)^2$ OpenStudy (anonymous):

It sqrt's the whole equation.... make sence? I hope OpenStudy (anonymous):

ok OpenStudy (anonymous):

so, let's start with each paranthetical group, focusing on the left one with root(2) OpenStudy (anonymous):

can you evaluate $\sqrt{2} - 5\sqrt{2}$ OpenStudy (anonymous):

got lost...yep OpenStudy (anonymous):

-4$-4\sqrt 2$ OpenStudy (anonymous):

now square it OpenStudy (anonymous):

$-8\sqrt3$ OpenStudy (anonymous):

thats where I'm lost....how do you ^2 a sqrt? OpenStudy (anonymous):

ok, so a square root is just this: you have a number, x, that you multiply by itself, x * x, to yield another value, x*x = y, so the square root of y is x. OpenStudy (anonymous):

$do you 16*2 then ^2 or do you ^ the 4 and the 2 separate?$ OpenStudy (anonymous):

square root of 2 is actually a value less than two. if you have multiply $\sqrt{2} * \sqrt{2}$ you'll get 2 OpenStudy (anonymous):

so in that case you had, y = x*x, so the square root of y is x, here you could say that y =2, therefore x = $\sqrt{2}$ OpenStudy (anonymous):

so you get 16 * 2 then square? OpenStudy (anonymous):

16 *2 is the result of $-4\sqrt{?}$ sqaured OpenStudy (anonymous):

sorry, that ? is a 2 OpenStudy (anonymous):

i'm confused as to why you square it again? OpenStudy (anonymous):

you've solved the left paranthetical group, so solve the right OpenStudy (anonymous):

$d=\sqrt (x2 -x1)^2 +(y2-y1)^2$ right? OpenStudy (anonymous):

this is the distance equation, yes OpenStudy (anonymous):

did you solve the problem? OpenStudy (anonymous):

1024+36864 right? OpenStudy (anonymous):

sqrt? right? OpenStudy (anonymous):

so you have 16*2 on the left and what on the right? i get 64 * 3 on the right OpenStudy (anonymous):

so that is 16*2 + 64*3 OpenStudy (anonymous):

squareroot( 16 *2 + 64*3 ), unless there are other operations missing in the original equation... OpenStudy (anonymous):

Sorry! I keep gettin stuck with trin to post my comments to you!! I got 1024 + 36864 then sqrt 37288? am I right so far? OpenStudy (anonymous):

i think the numbers you have are way too big, how did you get 1024? OpenStudy (anonymous):

I squared the 16*2 and 64*3....? OpenStudy (anonymous):

Are you still with me? If not then thanx for all your help...if you are then am I right or wher am I going wrong? OpenStudy (anonymous):

why did you square them? OpenStudy (anonymous):

you already did, that's how you have 16*2 and not -4*sqrt(2) OpenStudy (anonymous):

look at the prob again.....in th () you have to get the sqrt down to be squared... OpenStudy (anonymous):

If not then how do you ^ 2 a sqrt? OpenStudy (anonymous):

a sqrt is just a number that if you square that number, you get another number...so if you have $\sqrt{2}$, if you square that you get 2. if you "^2 a sqrt" those two operations are cancelling eachother out...so you did this when you found that OpenStudy (anonymous):

$(-4*\sqrt{2})^2 = 16 * 2$ OpenStudy (anonymous):

right there you squared a square root OpenStudy (anonymous):

oh, ok.... OpenStudy (anonymous):

rt(2) squared is 2 OpenStudy (anonymous):

so how do I do the -8 sqrt 3 ^2? OpenStudy (anonymous):

the same way as you did with the left, ;) so what is -8 squared? OpenStudy (anonymous):

64 OpenStudy (anonymous):

what is $\sqrt{3}$ squared? OpenStudy (anonymous):

3? OpenStudy (anonymous):

right OpenStudy (anonymous):

so you have 16*2 + 64*3 OpenStudy (anonymous):

so i sqrt 160? OpenStudy (anonymous):

you have 32 + 192 OpenStudy (anonymous):

that is the value you square root OpenStudy (anonymous):

the 32 is negative? OpenStudy (anonymous):

no..... OpenStudy (anonymous):

both value are positive, they were calculated from negative values that you then squared, and when you multiply two negative numbers you get a positive OpenStudy (anonymous):

So d=14.96? OpenStudy (anonymous):

right, $\sqrt{204}$ OpenStudy (anonymous):

So you are in Georgia IT? OpenStudy (anonymous): OpenStudy (anonymous):

$\sqrt{224}$ OpenStudy (anonymous):

yes, i am OpenStudy (anonymous): OpenStudy (anonymous):

where are you from? OpenStudy (anonymous):

Great Help!! Thanx more than you'll ever know!! Good ol' Tennessee OpenStudy (anonymous):

right on, no problem, :) OpenStudy (anonymous):

Maybe you can help me again soon!! God Bless! OpenStudy (anonymous):

of course, would be glad too OpenStudy (anonymous):

thanks

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