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OpenStudy (anonymous):
what do you want me to do
OpenStudy (anonymous):
solve the equation plz
OpenStudy (anonymous):
i got x= -1/2 or x= 1/2
OpenStudy (anonymous):
or x= -1 +or- root 17/ 8
OpenStudy (anonymous):
i got 1 do you mind to check a few others? could you show your work so i can make sure im doing them right?
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OpenStudy (anonymous):
do you want me to show the work for the one i just did
OpenStudy (anonymous):
yes plz
OpenStudy (anonymous):
and then
3x(x+3)=1
OpenStudy (anonymous):
x^2(4+(1/x)-(1/x^2))=0 gets rid of the denom
OpenStudy (anonymous):
then you have 4x^2+x-1
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OpenStudy (anonymous):
then use the quadratic equation to solve
OpenStudy (anonymous):
ok
OpenStudy (anonymous):
?
OpenStudy (anonymous):
???
OpenStudy (anonymous):
hello?
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OpenStudy (anonymous):
okay bye
OpenStudy (anonymous):
hello
OpenStudy (anonymous):
sorry it kicked me off. now can you find the real solution for the same equation plz
OpenStudy (anonymous):
and for 3x(x+2)=1
OpenStudy (anonymous):
hi
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OpenStudy (anonymous):
sry i thought you left
OpenStudy (anonymous):
tell me what you think you would do for that problem
OpenStudy (anonymous):
hi would you plz care to answer those 2 ?s only 1 more after that!
OpenStudy (anonymous):
well i have that the answer for the problem you just did should be .309 which should be no solution correct? i dont think i worked it right tho
OpenStudy (anonymous):
you mean the 3x(x+2)=1
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OpenStudy (anonymous):
hello?
OpenStudy (anonymous):
y do u keep leaving i can't help if u keep doin that
OpenStudy (anonymous):
and what would the real solution be for
4+(1/x)-(1/x^2)=0
OpenStudy (anonymous):
Its kicking me off sorry
OpenStudy (anonymous):
look above
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OpenStudy (anonymous):
what grade r u in?
OpenStudy (anonymous):
college al why does my grade matter
OpenStudy (anonymous):
that was solving that equation. not finding the real solution?
OpenStudy (anonymous):
it doesn't i just try to get a feel for who im helping
OpenStudy (anonymous):
high school
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OpenStudy (anonymous):
the real solution to any equation, like above with a degree of two it will be quadratic that means that the real solution is any point in which that equation crosses the x-axis or in other words the x-intercepts the term real refers to any solution that can be graphed on a real plane not including imaginary terms or number
OpenStudy (anonymous):
or if you are finding a solution to a pair of equations the solution represents the point where the two equations intersect
OpenStudy (anonymous):
ok and what would the real solution be for
4+(1/x)-(1/x^2)=0
OpenStudy (anonymous):
you haven'y given me any context clues that you are trying to solve two equations intersectio point, that means it will be the x-intercepts
OpenStudy (anonymous):
ok, do you have a graphing calc.?
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OpenStudy (anonymous):
what is the first step in trying to solve that equation?
OpenStudy (anonymous):
do not
and find a common den
OpenStudy (anonymous):
almost, we have to rationalize the denomintator, because this equation represents a function and only real solutions which can't have a denom. of zero therefore we must get rid of the variables in the denom.
OpenStudy (anonymous):
okay. and i would do that by?
OpenStudy (anonymous):
mulitply the entire equation on both sides by the largest variable in the denom.
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OpenStudy (anonymous):
you should get 4x^2+x-1
OpenStudy (anonymous):
okay and then?
i just realized we didnt go over this in class. we skiped this section
OpenStudy (anonymous):
what is college algebra?
OpenStudy (anonymous):
i have never heard of that?
OpenStudy (anonymous):
i'm in hs too, that's why i'm asking.
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OpenStudy (anonymous):
thanks for the help
OpenStudy (anonymous):
do you want me to finish
OpenStudy (anonymous):
alright then you would use the quadratic equation to solve
OpenStudy (anonymous):
what's the next question
OpenStudy (anonymous):
so the final answer is?
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OpenStudy (anonymous):
.39 or -.64
OpenStudy (anonymous):
then you check it in the original equation to make sure it works
OpenStudy (anonymous):
it works when i checked it, what's the next question
OpenStudy (anonymous):
thats all i have now. ive already check the others thanks for all your help
OpenStudy (anonymous):
ok, your welcome if you ever need help let me know