4+(1/x)-(1/x^2)=0
what do you want me to do
solve the equation plz
i got x= -1/2 or x= 1/2
or x= -1 +or- root 17/ 8
i got 1 do you mind to check a few others? could you show your work so i can make sure im doing them right?
do you want me to show the work for the one i just did
yes plz
and then 3x(x+3)=1
x^2(4+(1/x)-(1/x^2))=0 gets rid of the denom
then you have 4x^2+x-1
then use the quadratic equation to solve
ok
?
???
hello?
okay bye
hello
sorry it kicked me off. now can you find the real solution for the same equation plz
and for 3x(x+2)=1
hi
sry i thought you left
tell me what you think you would do for that problem
hi would you plz care to answer those 2 ?s only 1 more after that!
well i have that the answer for the problem you just did should be .309 which should be no solution correct? i dont think i worked it right tho
you mean the 3x(x+2)=1
hello?
y do u keep leaving i can't help if u keep doin that
and what would the real solution be for 4+(1/x)-(1/x^2)=0
Its kicking me off sorry
look above
what grade r u in?
college al why does my grade matter
that was solving that equation. not finding the real solution?
it doesn't i just try to get a feel for who im helping
high school
the real solution to any equation, like above with a degree of two it will be quadratic that means that the real solution is any point in which that equation crosses the x-axis or in other words the x-intercepts the term real refers to any solution that can be graphed on a real plane not including imaginary terms or number
or if you are finding a solution to a pair of equations the solution represents the point where the two equations intersect
ok and what would the real solution be for 4+(1/x)-(1/x^2)=0
you haven'y given me any context clues that you are trying to solve two equations intersectio point, that means it will be the x-intercepts
ok, do you have a graphing calc.?
what is the first step in trying to solve that equation?
do not and find a common den
almost, we have to rationalize the denomintator, because this equation represents a function and only real solutions which can't have a denom. of zero therefore we must get rid of the variables in the denom.
okay. and i would do that by?
mulitply the entire equation on both sides by the largest variable in the denom.
you should get 4x^2+x-1
okay and then? i just realized we didnt go over this in class. we skiped this section
what is college algebra?
i have never heard of that?
i'm in hs too, that's why i'm asking.
thanks for the help
do you want me to finish
alright then you would use the quadratic equation to solve
what's the next question
so the final answer is?
.39 or -.64
then you check it in the original equation to make sure it works
it works when i checked it, what's the next question
thats all i have now. ive already check the others thanks for all your help
ok, your welcome if you ever need help let me know
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