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OpenStudy (anonymous):

4+(1/x)-(1/x^2)=0

OpenStudy (anonymous):

what do you want me to do

OpenStudy (anonymous):

solve the equation plz

OpenStudy (anonymous):

i got x= -1/2 or x= 1/2

OpenStudy (anonymous):

or x= -1 +or- root 17/ 8

OpenStudy (anonymous):

i got 1 do you mind to check a few others? could you show your work so i can make sure im doing them right?

OpenStudy (anonymous):

do you want me to show the work for the one i just did

OpenStudy (anonymous):

yes plz

OpenStudy (anonymous):

and then 3x(x+3)=1

OpenStudy (anonymous):

x^2(4+(1/x)-(1/x^2))=0 gets rid of the denom

OpenStudy (anonymous):

then you have 4x^2+x-1

OpenStudy (anonymous):

then use the quadratic equation to solve

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

?

OpenStudy (anonymous):

???

OpenStudy (anonymous):

hello?

OpenStudy (anonymous):

okay bye

OpenStudy (anonymous):

hello

OpenStudy (anonymous):

sorry it kicked me off. now can you find the real solution for the same equation plz

OpenStudy (anonymous):

and for 3x(x+2)=1

OpenStudy (anonymous):

hi

OpenStudy (anonymous):

sry i thought you left

OpenStudy (anonymous):

tell me what you think you would do for that problem

OpenStudy (anonymous):

hi would you plz care to answer those 2 ?s only 1 more after that!

OpenStudy (anonymous):

well i have that the answer for the problem you just did should be .309 which should be no solution correct? i dont think i worked it right tho

OpenStudy (anonymous):

you mean the 3x(x+2)=1

OpenStudy (anonymous):

hello?

OpenStudy (anonymous):

y do u keep leaving i can't help if u keep doin that

OpenStudy (anonymous):

and what would the real solution be for 4+(1/x)-(1/x^2)=0

OpenStudy (anonymous):

Its kicking me off sorry

OpenStudy (anonymous):

look above

OpenStudy (anonymous):

what grade r u in?

OpenStudy (anonymous):

college al why does my grade matter

OpenStudy (anonymous):

that was solving that equation. not finding the real solution?

OpenStudy (anonymous):

it doesn't i just try to get a feel for who im helping

OpenStudy (anonymous):

high school

OpenStudy (anonymous):

the real solution to any equation, like above with a degree of two it will be quadratic that means that the real solution is any point in which that equation crosses the x-axis or in other words the x-intercepts the term real refers to any solution that can be graphed on a real plane not including imaginary terms or number

OpenStudy (anonymous):

or if you are finding a solution to a pair of equations the solution represents the point where the two equations intersect

OpenStudy (anonymous):

ok and what would the real solution be for 4+(1/x)-(1/x^2)=0

OpenStudy (anonymous):

you haven'y given me any context clues that you are trying to solve two equations intersectio point, that means it will be the x-intercepts

OpenStudy (anonymous):

ok, do you have a graphing calc.?

OpenStudy (anonymous):

what is the first step in trying to solve that equation?

OpenStudy (anonymous):

do not and find a common den

OpenStudy (anonymous):

almost, we have to rationalize the denomintator, because this equation represents a function and only real solutions which can't have a denom. of zero therefore we must get rid of the variables in the denom.

OpenStudy (anonymous):

okay. and i would do that by?

OpenStudy (anonymous):

mulitply the entire equation on both sides by the largest variable in the denom.

OpenStudy (anonymous):

you should get 4x^2+x-1

OpenStudy (anonymous):

okay and then? i just realized we didnt go over this in class. we skiped this section

OpenStudy (anonymous):

what is college algebra?

OpenStudy (anonymous):

i have never heard of that?

OpenStudy (anonymous):

i'm in hs too, that's why i'm asking.

OpenStudy (anonymous):

thanks for the help

OpenStudy (anonymous):

do you want me to finish

OpenStudy (anonymous):

alright then you would use the quadratic equation to solve

OpenStudy (anonymous):

what's the next question

OpenStudy (anonymous):

so the final answer is?

OpenStudy (anonymous):

.39 or -.64

OpenStudy (anonymous):

then you check it in the original equation to make sure it works

OpenStudy (anonymous):

it works when i checked it, what's the next question

OpenStudy (anonymous):

thats all i have now. ive already check the others thanks for all your help

OpenStudy (anonymous):

ok, your welcome if you ever need help let me know

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