write the equation for the the parabola
x-intercepts are 3 and 7 and with a minimum of -2
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Do you know any calculus? :D
Are you supposed to use calculus to figure out the problem? If so, it's a lot less tedious.
i dont know
Based on the intercepts, you know your equation factors down into (x-3)(x-7).
Multiplying it out gives x^2 - 10x + 21.
Your parabola also has a minimum at halfway between your intercepts, by reflection, at x = 5.
Plugging in 5 above gives -4, but we want -2, so we can multiply the equation by 1/2.
y = (1/2)*(x^2 - 10x + 21)